大约有 20,000 项符合查询结果（耗时：0.0316秒） [XML]
Never seen before C++ for loop
...loop is in the middle - between the two semicolons ;.
In C++ it is OK to put almost any expression as a condition: anything that evaluates to zero means false; non-zero means true.
In your case, the condition is u--: when you convert to C#, simply add != 0:
for (u = b.size(), v = b.back(); u-- !=...
Finding quaternion representing the rotation from one vector to another
I have two vectors u and v. Is there a way of finding a quaternion representing the rotation from u to v?
7 Answers
...
How to override trait function and call it from the overridden function?
...
Your last one was almost there:
trait A {
function calc($v) {
return $v+1;
}
}
class MyClass {
use A {
calc as protected traitcalc;
}
function calc($v) {
$v++;
return $this...
What are the complexity guarantees of the standard containers?
Apparently ;-) the standard containers provide some form of guarantees.
3 Answers
3
...
sed one-liner to convert all uppercase to lowercase?
...extfile in which some words are printed in ALL CAPS. I want to be able to just convert everything in the textfile to lowercase, using sed . That means that the first sentence would then read, 'i have a textfile in which some words are printed in all caps.'
...
Iterate through the fields of a struct in Go
Basically, the only way (that I know of) to iterate through the values of the fields of a struct is like this:
3 Answers
...
`elif` in list comprehension conditionals
Can we use elif in list comprehension?
6 Answers
6
...
Git flow release branches and tags - with or without “v” prefix
I have seen multiple contradicting definitions on various git flow related websites. Is there an official recommendation or single source of truth?
...
How do I get the YouTube video ID from a URL?
I want to get the v=id from YouTube’s URL with JavaScript (no jQuery, pure JavaScript).
39 Answers
...
Mounting multiple volumes on a docker container?
I know I can mount a directory in my host on my container using something like
5 Answers
...