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what does the __file__ variable mean/do?
I usually just hard-wire these with the actual path. But there is a reason for these statements that determine path at runtime, and I would really like to understand the os.path module so that I can start using it.
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How to reliably open a file in the same directory as a Python script
...th(
os.path.join(os.getcwd(), os.path.dirname(__file__)))
The join() call prepends the current working directory, but the documentation says that if some path is absolute, all other paths left of it are dropped. Therefore, getcwd() is dropped when dirname(__file__) returns an absolute path.
Als...
What is the iPad user agent?
... This answer is incorrect. From iOS 13 there is now no mention of iPad at all.
– CpnCrunch
Dec 16 '19 at 18:51
See th...
How many GCC optimization levels are there?
..., the default if no optimization level is specified)
-O1 (optimize minimally)
-O2 (optimize more)
-O3 (optimize even more)
-Ofast (optimize very aggressively to the point of breaking standard compliance)
-Og (Optimize debugging experience. -Og enables optimizations that do not interfere...
List all the modules that are part of a python package?
Is there a straightforward way to find all the modules that are part of a python package? I've found this old discussion , which is not really conclusive, but I'd love to have a definite answer before I roll out my own solution based on os.listdir().
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os.path.dirname(__file__) returns empty
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edited Oct 16 '11 at 22:42
answered Oct 16 '11 at 9:06
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Python list directory, subdirectory, and files
I'm trying to make a script to list all directory, subdirectory, and files in a given directory.
I tried this:
7 Answers
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python: Change the scripts working directory to the script's own directory
... __file__ fails in "frozen" programs (created using py2exe, PyInstaller, cx_Freeze). sys.argv[0] works. @ChrisDown: If you want to follow symlinks; os.path.realpath() could be used.
– jfs
Apr 5 '14 at 20:12
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How to identify platform/compiler from preprocessor macros?
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I'm sorry, but this answer is quite incorrect on all accounts and doesn't even answer the question.
– rubenvb
Jan 27 '15 at 20:13
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How to open every file in a folder?
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Os
You can list all files in the current directory using os.listdir:
import os
for filename in os.listdir(os.getcwd()):
with open(os.path.join(os.cwd(), filename), 'r') as f: # open in readonly mode
# do your stuff
Glob
Or you c...