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List of lists changes reflected across sublists unexpectedly
...(3)]
which will reevaluate [1]*4 each time instead of evaluating it once and making 3 references to 1 list.
You might wonder why * can't make independent objects the way the list comprehension does. That's because the multiplication operator * operates on objects, without seeing expressions. Wh...
How to detect if a script is being sourced
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This seems to be portable between Bash and Korn:
[[ $_ != $0 ]] && echo "Script is being sourced" || echo "Script is a subshell"
A line similar to this or an assignment like pathname="$_" (with a later test and action) must be on the first line of the s...
Waiting until two async blocks are executed before starting another block
When using GCD, we want to wait until two async blocks are executed and done before moving on to the next steps of execution. What is the best way to do that?
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In Clojure, when should I use a vector over a list, and the other way around?
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Once again, it seems I've answered my own question by getting impatient and asking it in #clojure on Freenode. Good thing answering your own questions is encouraged on Stackoverflow.com :D
I had a quick discussion with Rich Hickey, and here is the gist of it.
[12:21] <Raynes> Vectors a...
How does Duff's device work?
I've read the article on Wikipedia on the Duff's device , and I don't get it. I am really interested, but I've read the explanation there a couple of times and I still don't get it how the Duff's device works.
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Understanding “randomness”
I can't get my head around this, which is more random?
28 Answers
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Java's L number (long) specification
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There are specific suffixes for long (e.g. 39832L), float (e.g. 2.4f) and double (e.g. -7.832d).
If there is no suffix, and it is an integral type (e.g. 5623), it is assumed to be an int. If it is not an integral type (e.g. 3.14159), it is assumed to be a double.
In all other cases (byte, sho...
What is the result of % in Python?
...odulo operator always yields a result with the same sign as its second operand (or zero); the absolute value of the result is strictly smaller than the absolute value of the second operand [2].
Taken from http://docs.python.org/reference/expressions.html
Example 1:
6%2 evaluates to 0 because the...
Why is “int i = 2147483647 + 1;” OK, but “byte b = 127 + 1;” is not compilable?
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Constants are evaluated as ints, so 2147483647 + 1 overflows and gives you a new int, which is assignable to int, while 127 + 1 also evaluated as int equals to 128, and it is not assignable to byte.
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Uninstall / remove a Homebrew package including all its dependencies
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EDIT:
It looks like the issue is now solved using an external command called brew rmdeps or brew rmtree.
To install and use, issue the following commands:
$ brew tap beeftornado/rmtree
$ brew rmtree <package>
See the above link for more information and discussion.
Original answ...