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How to determine the number of days in a month in SQL Server?
...er of days in the month.
DECLARE @ADate DATETIME
SET @ADate = GETDATE()
SELECT DAY(EOMONTH(@ADate)) AS DaysInMonth
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Select + copy text in a TextView?
Is there a way to allow the user to select / copy text in a TextView? I need the same functionality of EditText where you can long-press the control and get the popup options of select all / copy, but I need the control to look like a TextView.
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Store select query's output in one array in postgres
...
There are two ways. One is to aggregate:
SELECT array_agg(column_name::TEXT)
FROM information.schema.columns
WHERE table_name = 'aean'
The other is to use an array constructor:
SELECT ARRAY(
SELECT column_name
FROM information.schema.columns
WHERE table_name = ...
System.Net.Http: missing from namespace? (using .net 4.5)
... Add Reference dialog right-click on your project in Solution Explorer and select Add Reference.... It should look something like:
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getting the ng-object selected with ng-change
Given the following select element
10 Answers
10
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Counting the number of option tags in a select tag in jQuery
How do I count the number of <option> s in a <select> DOM element using jQuery?
8 Answers
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You can't specify target table for update in FROM clause
...llow you to write queries like this:
UPDATE myTable
SET myTable.A =
(
SELECT B
FROM myTable
INNER JOIN ...
)
That is, if you're doing an UPDATE/INSERT/DELETE on a table, you can't reference that table in an inner query (you can however reference a field from that outer table...)
Th...
How can I make an entire HTML form “readonly”?
...e="text" name="something" placeholder="enter some text" />
<select>
<option value="0" disabled="disabled" selected="selected">select somethihng</option>
<option value="1">woot</option>
<option value="2">is</opt...
SQL to find the number of distinct values in a column
I can select all the distinct values in a column in the following ways:
11 Answers
11
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MySQL selecting yesterday's date
...get yesterday's date is:
subdate(current_date, 1)
Your query would be:
SELECT
url as LINK,
count(*) as timesExisted,
sum(DateVisited between UNIX_TIMESTAMP(subdate(current_date, 1)) and
UNIX_TIMESTAMP(current_date)) as timesVisitedYesterday
FROM mytable
GROUP BY 1
For the ...