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Algorithm to find Largest prime factor of a number
...factorisation. It makes use of the identity N = (a + b)(a - b) = a^2 - b^2 and is easy to understand and implement. Unfortunately it's not very fast in general.
The best known method for factoring numbers up to 100 digits long is the Quadratic sieve. As a bonus, part of the algorithm is easily done...
Weighted random numbers
I'm trying to implement a weighted random numbers. I'm currently just banging my head against the wall and cannot figure this out.
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The difference between Classes, Objects, and Instances
What is a class, an object and an instance in Java?
16 Answers
16
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Interview question: Check if one string is a rotation of other string [closed]
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First make sure s1 and s2 are of the same length. Then check to see if s2 is a substring of s1 concatenated with s1:
algorithm checkRotation(string s1, string s2)
if( len(s1) != len(s2))
return false
if( substring(s2,concat(s1,s1))
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How to get the first and last date of the current year?
Using SQL Server 2000, how can I get the first and last date of the current year?
18 Answers
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Is there a better way of writing v = (v == 0 ? 1 : 0); [closed]
I want to toggle a variable between 0 and 1. If it's 0 I want to set it to 1, else if it's 1 I want to set it to 0.
31 Answ...
How do you compare two version Strings in Java?
Is there a standard idiom for comparing version numbers? I can't just use a straight String compareTo because I don't know yet what the maximum number of point releases there will be. I need to compare the versions and have the following hold true:
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Logical XOR operator in C++?
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Note that this only works for booleans. And ^ would work perfectly well there. 2 !=1 => 1 which is not what you want! as LiraNuna says, putting a ! infront of both sides solves that problem. but again, then you can use bitwise ^...
– Brian...
Solving a “communications link failure” with JDBC and MySQL [duplicate]
... in different web sites, but non of them worked. Finally I changed my code and found out what was the problem. I'll try to tell you about different approaches and sum them up here.
While I was seeking the internet to find the solution for this error, I figured out that there are many solutions that...
How to find all positions of the maximum value in a list?
... 0 for this is 2n, the list is iterated through 2x, once to determine max, and another time to find the positions of the max. A for loop that tracks the current max and its position might be more efficient for really long lists.
– radtek
Jan 8 '15 at 18:42
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