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How to UPSERT (MERGE, INSERT … ON DUPLICATE UPDATE) in PostgreSQL?

...o do an upsert, which is what MySQL calls INSERT ... ON DUPLICATE UPDATE and the standard supports as part of the MERGE operation. ...
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mongodb: insert if not exists

...-find-else-update block entirely. It will insert if the key doesn't exist and will update if it does. Before: {"key":"value", "key2":"Ohai."} After: {"key":"value", "key2":"value2", "key3":"value3"} You can also specify what data you want to write: data = {"$set":{"key2":"value2"}} Now yo...
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When to use actors instead of messaging solutions such as WebSphere MQ or Tibco Rendezvous?

I've already read the question and answers to What design decisions would favour Scala's Actors instead of JMS? . 3 Answer...
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Android destroying activities, killing processes

Hi I'm wondering how Android is managing memory and I can't find precise answer anywhere. Let's assume I have an application with 5 activities on current activity stack (4 are stopped and 1 is resumed), there is no service connected. I press HOME button so that all of my activities are stopped. I st...
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Is there a JavaScript MVC (micro-)framework? [closed]

... Skip Backbone and go right for Spine. It's got a much more logical MVC implementation. – Chris Jaynes May 19 '12 at 5:27 ...
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C++ IDE for Linux? [closed]

I want to expand my programming horizons to Linux. A good, dependable basic toolset is important, and what is more basic than an IDE? ...
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Rename package in Android Studio

How do you rename packages in the new IDE Android Studio, based on IntelliJ IDEA? 52 Answers ...
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Cron jobs and random times, within given hours

I need the ability to run a PHP script 20 times a day at completely random times. I also want it to run only between 9am - 11pm. ...
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Java “lambda expressions not supported at this language level”

I was testing out some new features of Java 8 and copied the example into my IDE (Eclipse originally, then IntelliJ) as shown here ...
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Update value of a nested dictionary of varying depth

...ight general idea, i.e. a recursive solution, but somewhat peculiar coding and at least one bug. I'd recommend, instead: Python 2: import collections def update(d, u): for k, v in u.iteritems(): if isinstance(v, collections.Mapping): d[k] = update(d.get(k, {}), v) ...