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Unescape HTML entities in Javascript?
...of a div reduces the XSS vulnerability, but it is still problematic in IE9 and Firefox.
function htmlDecode(input){
var e = document.createElement('textarea');
e.innerHTML = input;
// handle case of empty input
return e.childNodes.length === 0 ? "" : e.childNodes[0].nodeValue;
}
htmlDecode...
Expand/collapse section in UITableView in iOS
Could somebody tell me the way to perform UITableView expandable/collapsible animations in sections of UITableView as below?
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How do Mockito matchers work?
Mockito argument matchers (such as any , argThat , eq , same , and ArgumentCaptor.capture() ) behave very differently from Hamcrest matchers.
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PHP & mySQL: Year 2038 Bug: What is it? How to solve it?
...break it up into small parts so that it is easy for novice users to understand as well. So my question(s):
6 Answers
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SSH library for Java [closed]
...e Java Secure Channel (JSCH) is a very popular library, used by maven, ant and eclipse. It is open source with a BSD style license.
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How to use OpenSSL to encrypt/decrypt files?
I want to crypt and decrypt one file using one password.
10 Answers
10
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Debugging WebSocket in Google Chrome
...ing through a WebSocket? For debugging purposes I'd like to see the client and server requests/responses.
11 Answers
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How to cherry-pick multiple commits
...hes. Commit a is the head of one, while the other has b , c , d , e and f on top of a . I want to move c , d , e and f to first branch without commit b . Using cherry pick it is easy: checkout first branch cherry-pick one by one c to f and rebase second branch onto first. But is...
Getting the last argument passed to a shell script
...last
This one is also pretty portable (again, should work with bash, ksh and sh) and it doesn't shift the arguments, which could be nice.
It uses the fact that for implicitly loops over the arguments if you don't tell it what to loop over, and the fact that for loop variables aren't scoped: they ...
Swapping two variable value without using third variable
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*x ^= *y;
}
}
Why the test?
The test is to ensure that x and y have different memory locations (rather than different values). This is because (p xor p) = 0 and if both x and y share the same memory location, when one is set to 0, both are set to 0.
When both *x and *y are 0, all o...