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Showing the same file in both columns of a Sublime Text window
...indowCommand):
def run(self):
w = self.window
if w.num_groups() == 1:
w.run_command('set_layout', {
'cols': [0.0, 1.0],
'rows': [0.0, 0.33, 1.0],
'cells': [[0, 0, 1, 1], [0, 1, 1, 2]]
})
w.focus_g...
Regular Expressions and negating a whole character group [duplicate]
...nt mode
^ # match start of line/string
(?: # begin non-capturing group
(?! # begin negative lookahead
ab # literal text sequence ab
) # end negative lookahead
. # any single character
) # end non-capturing group
+ # repeat previous match one or more times
$...
Testing modules in rspec
...llo.should == "hallo" }
end
It might seem wrong to hijack nested example groups, but I like the terseness. Any thoughts?
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MongoDB仿关系型数据库Group聚合例子 - 大数据 & AI - 清泛网 - 专注C/C++及内核技术
MongoDB仿关系型数据库Group聚合例子MongoDB Group,max仿关系型数据库例子，通过BsonJavaScript脚本实现。相当的SQL：select * from GroupDemo a right join (select userName,max(date) maxdate from GroupDemo group by userName) b on a date=b maxdate
namespace MongoGroupDemo
{
...
Remove rows with duplicate indices (Pandas DataFrame and TimeSeries)
... far the least performant for the provided example. Furthermore, while the groupby method is only slightly less performant, I find the duplicated method to be more readable.
Using the sample data provided:
>>> %timeit df3.reset_index().drop_duplicates(subset='index', keep='first').set_index...
Count the occurrences of DISTINCT values
...
SELECT name,COUNT(*) as count
FROM tablename
GROUP BY name
ORDER BY count DESC;
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How do I trim whitespace?
...e('\\s*(.*\\S)?\\s*')
>>> m=p.match(' \t blah ')
>>> m.group(1)
'blah'
>>> m=p.match(' \tbl ah \t ')
>>> m.group(1)
'bl ah'
>>> m=p.match(' \t ')
>>> print m.group(1)
None
Searching (you have to handle the "only spaces" input case diffe...
best way to add license section to iOS settings bundle
...to solve all the problems I was running into.
It seems to be best to use group element titles to hold the licenses (this is what Apple do in the iWork apps). There is however a limit on the length of these (and I've not yet discovered exactly what the limit is), so you need to break each license f...
How to include “zero” / “0” results in COUNT aggregate?
...erson
LEFT JOIN appointment ON person.person_id = appointment.person_id
GROUP BY person.person_id;
The reason why this is working, is that the outer (left) join will return NULL for those persons that do not have an appointment. The aggregate function count() will not count NULL values and thus...
Linq to Objects: does GroupBy preserve order of elements?
Does Enumerable.GroupBy from LINQ to Objects preserve order of elements in the groups?
1 Answer
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