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Can an Option in a Select tag carry multiple values?

I got a select tag with some options in a HTML form: (the data will be collected and processed using PHP) 15 Answers ...
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Can we have multiple “WITH AS” in single sql - Oracle SQL

... You can do this as: WITH abc AS( select FROM ...) , XYZ AS(select From abc ....) /*This one uses "abc" multiple times*/ Select From XYZ.... /*using abc, XYZ multiple times*/ ...
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How can I get this ASP.NET MVC SelectList to work?

I create a selectList in my controller, to display in the view. 23 Answers 23 ...
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Select by partial string from a pandas DataFrame

...ns of which 2 contain string values. I was wondering if there was a way to select rows based on a partial string match against a particular column? ...
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Search an Oracle database for tables with specific column names?

... To find all tables with a particular column: select owner, table_name from all_tab_columns where column_name = 'ID'; To find tables that have any or all of the 4 columns: select owner, table_name, column_name from all_tab_columns where column_name in ('ID', 'FNAME', ...
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How can I set the value of a DropDownList using jQuery?

... have described above, yet the range validator keeps failing telling me to select a value (when the value selected is within range). Please see my question stackoverflow.com/questions/3165033/… – James Jul 7 '10 at 13:14 ...
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Paging with Oracle

... Say, if I pass 10 as a page number, and 120 as number of pages, from the select statement it would give me the 1880th through 1200th, or something like that, my math in my head might be off. ...
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How to get a number of random elements from an array?

...- Math.random()); // Get sub-array of first n elements after shuffled let selected = shuffled.slice(0, n); DEMO: share | improve this answer | follow | ...
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Select mySQL based only on month and year

... SELECT * FROM projects WHERE YEAR(Date) = 2011 AND MONTH(Date) = 5 share | improve this answer | f...
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How to count occurrences of a column value efficiently in SQL?

... This should work: SELECT age, count(age) FROM Students GROUP by age If you need the id as well you could include the above as a sub query like so: SELECT S.id, S.age, C.cnt FROM Students S INNER JOIN (SELECT age, count(age) a...