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How to generate a create table script for an existing table in phpmyadmin?
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+1. Note: if running query from command line, the ; at the end is required.
– Withheld
Oct 22 '13 at 13:21
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Firebug-like debugger for Google Chrome
...g-like tool already built into Chrome. Just right click anywhere on a page and choose "Inspect element" from the menu. Chrome has a graphical tool for debugging (like in Firebug), so you can debug JavaScript. It also does CSS inspection well and can even change CSS rendering on the fly.
For more in...
What are the benefits of Java's types erasure?
...erned with the Twitter user. It's helpful to keep focused on the messages and not the messenger. There is a fairly consistent message with even just the excerpts mentioned thus far:
It's funny when Java users complain about type erasure, which is the only thing Java got right, while ignoring all ...
Connecting to remote URL which requires authentication using Java
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How do you handle a bad authentication event? [For example, if the user supplies username and password authentication credentials that don't match anything]?
– SK9
Aug 14 '11 at 6:06
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How to create a CPU spike with a bash command
...want to create a near 100% load on a Linux machine. It's quad core system and I want all cores going full speed. Ideally, the CPU load would last a designated amount of time and then stop. I'm hoping there's some trick in bash. I'm thinking some sort of infinite loop.
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How to make zsh run as a login shell on Mac OS X (in iTerm)?
...n iTerm -> Preferences -> Profiles Tab -> General section set Command to: /bin/zsh --login
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How to get last N records with activerecord?
...unnecessary to order the data twice, I'm currently getting the count first and using it with offset
– JtR
Jan 7 '09 at 14:12
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How can I run a directive after the dom has finished rendering?
...nswered Sep 3 '12 at 6:41
Artem AndreevArtem Andreev
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An App ID with Identifier '' is not available. Please enter a different string
I am trying to add a new APP ID to prepare for App Store submission and got the following error under the bundle ID I provided.
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Using JQuery - preventing form from submitting
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Two things stand out:
It possible that your form name is not form. Rather refer to
the tag by dropping the #.
Also the e.preventDefault is the correct JQuery syntax, e.g.
//option A
$("form").submit(function(e){
e.prev...