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When I catch an exception, how do I get the type, file, and line number?
...s.exc_info()
fname = os.path.split(exc_tb.tb_frame.f_code.co_filename)[1]
print(exc_type, fname, exc_tb.tb_lineno)
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edited Jan 29 '19 at 14:26
answered Aug 24 '18 at 3:36
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int3int3
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