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How to convert linq results to HashSet or HashedSet

...or generic methods to do it for us. Now you could choose to name it ToSet and return ISet<T> - but I'd stick with ToHashSet and the concrete type. This is consistent with the standard LINQ operators (ToDictionary, ToList) and allows for future expansion (e.g. ToSortedSet). You may also want t...
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How to merge the current branch into another branch

I have two branches, master and dev. I always work on dev and only check code into the master branch once it's been approved for production use. When I do so, I have to do the following: ...
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How to dynamically change a web page's title?

... Update: as per the comments and reference on SearchEngineLand most web crawlers will index the updated title. Below answer is obsolete, but the code is still applicable. You can just do something like, document.title = "This is the new page title...
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Remove duplicate rows in MySQL

... The aforementioned bug @DarkMantis referred to and it's solution. – Jordan Arseno Jan 23 '13 at 20:47 ...
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What do the terms “CPU bound” and “I/O bound” mean?

What do the terms "CPU bound" and "I/O bound" mean? 11 Answers 11 ...
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How do I change the highlight style in Vim spellcheck?

...rk|light) or colorscheme {schemename}). See also :h hl-SpellBad for names and descriptions of other Spell* highlight groups. share | improve this answer | follow ...
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Exporting data In SQL Server as INSERT INTO

I am using SQL Server 2008 Management Studio and have a table I want to migrate to a different db server. 11 Answers ...
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What is the “-->” operator in C++?

After reading Hidden Features and Dark Corners of C++/STL on comp.lang.c++.moderated , I was completely surprised that the following snippet compiled and worked in both Visual Studio 2008 and G++ 4.4. ...
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How to set JAVA_HOME in Linux for all users

I am new to Linux system and there seem to be too many Java folders. 20 Answers 20 ...
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For i = 0, why is (i += i++) equal to 0?

...ation): int i = 0; i = i + i; // i=0 because the ++ is a postfix operator and hasn't been executed i + 1; // Note that you are discarding the calculation result What actually happens is more involved than that - take a look at MSDN, 7.5.9 Postfix increment and decrement operators: The run-tim...