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How do I make a matrix from a list of vectors in R?

... 124 One option is to use do.call(): > do.call(rbind, a) [,1] [,2] [,3] [,4] [,5] [,6] [...
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Regular expression that matches valid IPv6 addresses

... 254 I was unable to get @Factor Mystic's answer to work with POSIX regular expressions, so I wrote o...
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Remove duplicate elements from array in Ruby

... | edited May 20 at 4:57 the Tin Man 147k3131 gold badges192192 silver badges272272 bronze badges ...
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What is the ultimate postal code and zip regex?

...le IMO. But you would still be missing on the validation part: Zip code 12345 may exist, but 12346 not, maybe 12344 doesn't exist either. How do you check for that with a regex? You can't. share | ...
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Maximum number of characters using keystrokes A, Ctrl+A, Ctrl+C and Ctrl+V

... 14 Answers 14 Active ...
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C++并发编程(中文版) - 文档下载 - 清泛网 - 专注C/C++及内核技术

...的并发… 1 1.1.2 并发的方法… 3 1.2 为什么使用并发… 4 1.2.1 因划分重点而使用并发… 5 1.2.2 为了提高性能而使用并发… 5 1.2.3 什么时候不使用并发… 6 1.3 在C++中使用并发和多线程… 7 1.3.1 多线程在C++中的发展历程… 7 1.3.2...
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What is the optimal Jewish toenail cutting algorithm?

...ort ifilter, permutations validseqs = ifilter(isValid, permutations([1,2,3,4,5])) for i in validseqs: print i (1, 3, 5, 2, 4) (1, 4, 2, 5, 3) (2, 4, 1, 3, 5) (2, 4, 1, 5, 3) (2, 5, 3, 1, 4) (3, 1, 4, 2, 5) (3, 1, 5, 2, 4) (3, 5, 1, 4, 2) (3, 5, 2, 4, 1) (4, 1, 3, 5, 2) (4, 2, 5, 1, 3) (4, 2, 5,...
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How to get row from R data.frame

...for example: #Add your data x <- structure(list(A = c(5, 3.5, 3.25, 4.25, 1.5 ), B = c(4.25, 4, 4, 4.5, 4.5 ), C = c(4.5, 2.5, 4, 2.25, 3 ) ), .Names = c("A", "B", "C"), class = "data.f...
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How to select .NET 4.5.2 as a target framework in Visual Studio

I have installed .NET Framework 4.5.2 on Windows 8.1. But in Visual Studio 2013 I do not see the .NET Framework 4.5.2 option (see screenshot). How do I target my project for .NET 4.5.2? ...
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Assign multiple columns using := in data.table, by group

...b col1 col2 # 1: 1 1 hi hello # 2: 2 2 hi hello # 3: 3 3 hi hello # 4: 1 4 hi hello # 5: 2 5 hi hello # 6: 3 6 hi hello x[ , c("mean", "sum") := list(mean(b), sum(b)), by = a][] # a b col1 col2 mean sum # 1: 1 1 hi hello 2.5 5 # 2: 2 2 hi hello 3.5 7 # 3: 3 3 hi hello ...