大约有 2,000 项符合查询结果(耗时:0.0035秒) [XML]
nvarchar和varchar相互转换、联合查询 - ORACLE - 清泛IT论坛,有思想、有深度
...帖最后由 zqp2013 于 2015-2-27 16:42 编辑
场景:联合查询(union all)Oracle两张表,同一组字段的数据类型不一致,分别是nvarchar和varchar。
这时联合查询报错如下:ora12704:字符集不匹配。
解决方法:需要对数据类型进行转换。
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MySql安装配置 - 爬虫/数据库 - 清泛IT社区,为创新赋能!
...端,解压
2.安装Mysql服务:
进入bin目录,mysqld.exe --install (指定安装的MySql服务名)。
(卸载 net stop servicename;
mysqld.exe --remove servicename)
3.进入MySql命令模式:
mysql.exe(回车)
4.赋...
自定义下载器扩展:个性化下载进度展示 - App Inventor 2 拓展 - 清泛IT社...
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离线版启动超时,有报错日志 - App Inventor 2 离线版 - 清泛IT社区,为创新赋能!
...ources\app.asar.unpacked\OpenJDK\bin\java, --add-opens=java.base/java.lang=ALL-UNNAMED, -Xmx4G, --add-opens, java.base/java.net=ALL-UNNAMED, --add-opens, java.base/sun.net.www.protocol.http=ALL-UNNAMED, --add-opens, java.base/sun.net.www.protocol.https=ALL-UNNAMED, -Dfile.encoding=UTF-8, -classpath,...
MySQL ('root'@'%') does not exist 的问题 - 爬虫/数据库 - 清泛IT社区,为创新赋能!
...mysql ,执行
mysql -u root -pPasswd
mysql >grant all privileges on *.* to root@"%" identified by "Passwd" ;
mysql >flush privileges;
error: ‘uint16_t’ does not name a type - c++1y / stl - 清泛IT社区,为创新赋能!
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【可动态编辑表格】App Inventor 2 Dynamic Editable HTML Table - App应用...
olor=rgba(0, 0, 0, 0.54)This example will allow you to:
Display an AI2 (in csv format e.g. header row, then data rows) list in an html table. It will also allow you (with the exception of the header row) to create new rows, edit any row, and delete any row, whilst returning the saved/upd...
【研究中】高德地图API研究及接入 - App应用开发 - 清泛IT社区,为创新赋能!
...0003,39.991957&key=<用户的key>&radius=1000&extensions=all
路径规划:https://lbs.amap.com/api/webservice/guide/api/direction
路径规划2.0:https://lbs.amap.com/api/webservice/guide/api/newroute
高德地图支持XYZ格式。XYZ格式是一种瓦片地图服务,...
【天气API】对接国内免费好用的天气API - App应用开发 - 清泛IT社区,为创新赋能!
...ather/weatherInfo?key=【你的_API_KEY】8&city=110000&extensions=all
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阿里云也有天气API。中国天气 weather.com.cn 虽然很权威,但是不对外提供API,网上的多数链接都失效了,不考虑。
优先选择高德。
参考:https://zhuanlan.z...
c++ boost::multi_index composite keys efficiency - c++1y / stl - 清泛IT社区,为创新赋能!
...ey and thus is slower?For example, if I was to maintain two containers manually using two different indices and wanted to find items that matched a specific 2-part query I would probably filter the first container for all items matching the 1st part of the query, and then filter the result for items...