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Is there a way to select sibling nodes?
...s(target) || [],
next = nexSiblings(target) || [];
return prev.concat(next);
}
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Insert spaces between words on a camel-cased token [duplicate]
...e Stuff And Sell It (IIRC).
Syntax explanation (credit):
{Ll} is Unicode Character Category "Letter lowercase" (as opposed to {Lu} "Letter uppercase"). P is a negative match, while p is a positive match, so \P{Ll} is literally "Not lowercase" and p{Ll} is "Lowercase".
So this regex splits on two p...
Merge and interleave two arrays in Ruby
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[ "a", "b" ].concat( ["c", "d"] ) #=> [ "a", "b", "c", "d" ]
– Leo Romanovsky
Oct 4 '12 at 4:41
31
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Linux Glibc幽灵漏洞允许黑客远程获取系统权 - 操作系统(内核) - 清泛网 - ...
...de <string.h> #include <errno.h> #define CANARY"in_the_coal_mine" struct { char buffer[1024]; char canary[sizeof(CANARY)]; } temp = { "buffer", CANARY }; int main(void) { struct hostent resbuf; struct hostent *result; int herrno; int retval; /*** strlen (name) = size_needed -sizeof (*host_addr) - si...
How to match “any character” in regular expression?
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Yes, you can. That should work.
. = any char
\. = the actual dot character
.? = .{0,1} = match any char zero or one times
.* = .{0,} = match any char zero or more times
.+ = .{1,} = match any char one or more times
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How to create strings containing double quotes in Excel formulas?
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Have you tried escaping with a double-quote?
= "Maurice ""The Rocket"" Richard"
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C++ convert hex string to signed integer
...iostream>
using namespace std;
int main() {
string s = "abcd";
char * p;
long n = strtol( s.c_str(), & p, 16 );
if ( * p != 0 ) { //my bad edit was here
cout << "not a number" << endl;
}
else {
cout << n << endl;
}
}
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How do I initialize a byte array in Java?
...;
for (int i = 0; i < len; i += 2) {
data[i / 2] = (byte) ((Character.digit(s.charAt(i), 16) << 4)
+ Character.digit(s.charAt(i+1), 16));
}
return data;
}
If you let CDRIVES static and final, the performance drop is irrelevant.
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Can I multiply strings in Java to repeat sequences? [duplicate]
...lain Java with no dependencies is the following one-liner:
new String(new char[generation]).replace("\0", "-")
Replace generation with number of repetitions, and the "-" with the string (or char) you want repeated.
All this does is create an empty string containing n number of 0x00 characters, a...
Why does the C preprocessor interpret the word “linux” as the constant “1”?
...LT_MIN__ 1.17549435082228750797e-38F
#define __UINT_LEAST8_TYPE__ unsigned char
#define __INTMAX_C(c) c ## L
#define __CHAR_BIT__ 8
#define __UINT8_MAX__ 255
#define __WINT_MAX__ 2147483647
#define __ORDER_LITTLE_ENDIAN__ 1234
#define __SIZE_MAX__ 18446744073709551615UL
#define __WCHAR_MAX__ 2147483...