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How do you know when to use fold-left and when to use fold-right?
...ee it. It's "haskell-style pseudocode". :)
– laughing_man
Apr 21 '15 at 2:38
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instantiate a class from a variable in PHP?
...you work with namespace, put the current namespace into the string: $var = __NAMESPACE__ . '\\' . $var . 'Class';
– bastey
Sep 2 '13 at 13:28
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How do I run a Ruby file in a Rails environment?
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#!/usr/bin/env /Users/me/rails_project/script/rails runner
Product.all.each { |p| p.price *= 2 ; p.save! }
-------------------------------------------------------------
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How do I set a conditional breakpoint in gdb, when char* x points to a string whose value equals “he
...
This method can have side effects. $_streq method from @tlwhitec is better.
– rools
Apr 14 '19 at 14:08
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Extending the User model with custom fields in Django
...ing the fields for additional information. This one-to-one model is often called a profile model, as it might store non-auth related information about a site user.
That said, extending django.contrib.auth.models.User and supplanting it also works...
Substituting a custom User model
Some kinds of p...
C++ map access discards qualifiers (const)
...k up a key without modifying the map.
find() returns an iterator, or const_iterator to an std::pair containing both the key (.first) and the value (.second).
In C++11, you could also use at() for std::map. If element doesn't exist the function throws a std::out_of_range exception, in contrast to o...
Is it possible to use “/” in a filename?
...hould ever be done, but is there a way to use the slash character that normally separates directories within a filename in Linux?
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SQL Server Escape an Underscore
...IKE keyword and the [ ] wildcard characters.
For your case:
... LIKE '%[_]d'
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How to convert a java.util.List to a Scala list
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import scala.collection.JavaConversions._
will do implicit conversion for you; e.g.:
var list = new java.util.ArrayList[Int](1,2,3)
list.foreach{println}
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Why use Ruby's attr_accessor, attr_reader and attr_writer?
...write classes which will work correctly no matter how their public API is called.
class Person
attr_accessor :age
...
end
Here, I can see that I may both read and write the age.
class Person
attr_reader :age
...
end
Here, I can see that I may only read the age. Imagine that it is set ...