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Add a property to a JavaScript object using a variable as the name?
...out modifying but it's referenced by other questions that are about dynamically creating objects and so I ended up here and happily benefited from this answer.
– Oliver Lloyd
Oct 29 '16 at 17:40
...
jsoncpp 不能处理__int64(long long)类型数据 - C/C++ - 清泛网 - 专注C/C++及内核技术
jsoncpp 不能处理__int64(long long)类型数据jsoncpp，是一个c++的解析和生成json的开源工具。如果你的c++程序需要解析或生成json，它会使这个过程变得很简单！但是，今天在用jsoncpp进...jsoncpp，是一个c++的解析和生成json的开源工具。如...
MongoDB仿关系型数据库Group聚合例子 - 大数据 & AI - 清泛网 - 专注C/C++及内核技术
...数据
Dictionary dic = new Dictionary();
dic["_userName"] = ""; // 与原字段名区分开
dic["_date"] = "";
dic["_data"] = "0";
MongoServer server = new MongoClient(MongoConnStr).GetServer();
MongoDatabase db = serve...
Visual Studio 2013 Update 4【VS2013 SP4 旗舰版下载地址】 - 更多技术 - ...
...(Chinese-Simplified)：7255 MB
发布日期： 2014/11/12
文件名： cn_visual_studio_ultimate_2013_with_update_4_x86_dvd_5935081.iso
语言： Chinese - Simplified
SHA1：5F924E3B8F6715F92DCD2F8E58558833D310A146
http://download.microsoft.com/do ... s2013.4_ult_chs.iso
Visual Studio Ultima...
Visual Studio 2013 Update 4【VS2013 SP4 旗舰版下载地址】 - 其他 - 清泛...
...(Chinese-Simplified)：7255 MB
发布日期： 2014/11/12
文件名： cn_visual_studio_ultimate_2013_with_update_4_x86_dvd_5935081.iso
语言： Chinese - Simplified
SHA1：5F924E3B8F6715F92DCD2F8E58558833D310A146
http://download.microsoft.com/do ... s2013.4_ult_chs.iso
Visual Studio Ultima...
Is it possible to use getters/setters in interface definition?
At the moment, TypeScript does not allow use get/set methods(accessors) in interfaces.
For example:
4 Answers
...
How to use Global Variables in C#?
...er the behavior of static variables declared inside, but it doesn't look really useful.
– Tommaso Belluzzo
Feb 2 at 18:01
...
Reading binary file and looping over each byte
...hile byte != "":
# Do stuff with byte.
byte = f.read(1)
finally:
f.close()
Python 2.5-2.7
with open("myfile", "rb") as f:
byte = f.read(1)
while byte != "":
# Do stuff with byte.
byte = f.read(1)
Note that the with statement is not available in versio...
Given a view, how do I get its viewController?
...nd
This macro avoids category pollution:
#define UIViewParentController(__view) ({ \
UIResponder *__responder = __view; \
while ([__responder isKindOfClass:[UIView class]]) \
__responder = [__responder nextResponder]; \
(UIViewController *)__responder; \
})
...
Find intersection of two nested lists?
... 3 filter returns an iterable instead of list, so you need to wrap filter calls with list():
c3 = [list(filter(lambda x: x in c1, sublist)) for sublist in c2]
Explanation:
The filter part takes each sublist's item and checks to see if it is in the source list c1.
The list comprehension is exec...