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How to check a radio button with jQuery?

...e: $("#radio_1").attr('checked', 'checked'); Tip: You may also want to call click() or change() on the radio button afterwards. See comments for more info. share | improve this answer | ...
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How do you trigger a block after a delay, like -performSelector:withObject:afterDelay:?

Is there a way to call a block with a primitive parameter after a delay, like using performSelector:withObject:afterDelay: but with an argument like int / double / float ? ...
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How to capture stdout output from a Python function call?

...ager: from io import StringIO import sys class Capturing(list): def __enter__(self): self._stdout = sys.stdout sys.stdout = self._stringio = StringIO() return self def __exit__(self, *args): self.extend(self._stringio.getvalue().splitlines()) del se...
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Why does HTML5 form-validation allow emails without a dot?

... I wonder when the last time someone actually sent an email to localhost! – Matthew Lock May 19 '17 at 3:14 2 ...
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Vertical line using XML drawable

...more complex view that I want to use as a drawable for the background of a table cell. There are different types of shapes/gradients/lines there. Using a view WOULD be a solution, however I would have to put it in a different drawing "layer" and that is potentially shooting yourself in the foot when...
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Hidden features of Perl?

What are some really useful but esoteric language features in Perl that you've actually been able to employ to do useful work? ...
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Twitter API returns error 215, Bad Authentication Data

I am trying to call following Twitter's API to get a list of followers for a user. 15 Answers ...
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Finding local maxima/minima with Numpy in a 1D numpy array

... If you are looking for all entries in the 1d array a smaller than their neighbors, you can try numpy.r_[True, a[1:] < a[:-1]] & numpy.r_[a[:-1] < a[1:], True] You could also smooth your array before this step using numpy.convolve(). I...
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Check if a value is within a range of numbers

...u're asking a question about numeric comparisons, so regular expressions really have nothing to do with the issue. You don't need "multiple if" statements to do it, either: if (x >= 0.001 && x <= 0.009) { // something } You could write yourself a "between()" function: function b...
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How to find indices of all occurrences of one string in another in JavaScript?

I'm trying to find the positions of all occurrences of a string in another string, case-insensitive. 13 Answers ...