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Responding with a JSON object in Node.js (converting object/array to JSON string)
...y:
function random(response) {
console.log("Request handler random was called.");
response.writeHead(200, {"Content-Type": "application/json"});
var otherArray = ["item1", "item2"];
var otherObject = { item1: "item1val", item2: "item2val" };
var json = JSON.stringify({
anObject: othe...
How is a non-breaking space represented in a JavaScript string?
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  is a HTML entity. When doing .text(), all HTML entities are decoded to their character values.
Instead of comparing using the entity, compare using the actual raw character:
var x = td.text();
if (x == '\xa0') { // Non-breakable space is char 0xa0 (160 dec)
x...
inserting characters at the start and end of a string
... answered Apr 8 '12 at 1:00
AkavallAkavall
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iOS: Access app-info.plist variables in code
...ode (right click the info.plist - select Open As) then you will get to see all the various key names you can use.
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Responsive website zoomed out to full width on mobile
...ar and I have a demo website. When I resize the browser on a desktop, it all works fine including the nav bar which become collapsible menu with a small icon on the top which I can click to see more menu buttons.
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Handler is abstract ,cannot be instantiated
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@Glenn--, srsly, this just solved all manner of other errors in my code. ++ to this answer!
– Joel Balmer
Mar 12 '14 at 22:28
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jQuery form serialize - empty string
...led. Those inputs will not show up in the serialized string. In my case, all form inputs had values but were disabled, resulting in an empty string being returned.
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Detect if homebrew package is installed
...out to write a shell script to detect if several homebrew packages are installed in the system. Is there a way to use a brew command to achieve that?
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what is the difference between ?:, ?! and ?= in regex?
...ng the pure regular expression. Perhaps I can but I would have to rely on callback functions.
– Y. Yoshii
May 16 '18 at 7:17
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Iterate an iterator by chunks (of n) in Python? [duplicate]
...y_list[i:i + chunk_size] for i in range(0, len(my_list), chunk_size)]
Finally, a solution that works on general iterators an behaves as desired is
def grouper(n, iterable):
it = iter(iterable)
while True:
chunk = tuple(itertools.islice(it, n))
if not chunk:
return...