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How do I convert NSMutableArray to NSArray?
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However, casting to (NSArray *) still allows a cast back up to (NSMutable *). Ain't that the case?
– sharvey
Nov 20 '10 at 2:22
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SQL Server Text type vs. varchar data type [closed]
...ts in your database
If you do not search on the value of the column
If you select this column rarely and do not join on it.
VARCHAR is good:
If you store little strings
If you search on the string value
If you always select it or use it in joins.
By selecting here I mean issuing any queries that ...
ListView addHeaderView causes position to increase by one?
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also you have to cast the item in this case.
– njzk2
Dec 23 '13 at 17:20
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C# Entity-Framework: How can I combine a .Find and .Include on a Model Object?
... latter (SingleOrDefault), ToList will retrieve all entries first and then select one
– Sander Rijken
Sep 8 '11 at 13:51
5
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Why should I use a pointer rather than the object itself?
...m (especially when using IDEs or text editors that show the signature of a selected functions). Also, const&.
– JAB
Mar 3 '14 at 16:04
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Why should I care that Java doesn't have reified generics?
... There is absolutely no need for reification to be able to do that. Method selection is done at compile time when the compile-time type information is available.
– Tom Hawtin - tackline
Dec 18 '09 at 13:25
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New Array from Index Range Swift
...laring your array to begin with.
EDIT:
To fix your function, you have to cast your Slice to an array:
func aFunction(numbers: Array<Int>, position: Int) -> Array<Int> {
var newNumbers = Array(numbers[0..<position])
return newNumbers
}
// test
aFunction([1, 2, 3], 2) // ...
Resolving MSB3247 - Found conflicts between different versions of the same dependent assembly
...ing up the Options dialog (Tools -> Options...).
In the left-hand tree, select the Projects and Solutions node, and then select Build and Run.
Note: if this node doesn't show up, make sure that the checkbox at the bottom of the dialog Show all settings is checked.
In the tools/options page th...
Java: how do I get a class literal from a generic type?
...pe erasure.
Java generics are little more than syntactic sugar for Object casts. To demonstrate:
List<Integer> list1 = new ArrayList<Integer>();
List<String> list2 = (List<String>)list1;
list2.add("foo"); // perfectly legal
The only instance where generic type information...
Converting java.util.Properties to HashMap
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The efficient way to do that is just to cast to a generic Map as follows:
Properties props = new Properties();
Map<String, String> map = (Map)props;
This will convert a Map<Object, Object> to a raw Map, which is "ok" for the compiler (only warning)....