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How do I create a random alpha-numeric string in C++?
I'd like to create a random string, consisting of alpha-numeric characters. I want to be able to be specify the length of the string.
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Structure padding and packing
...s the following "gaps" into your first structure:
struct mystruct_A {
char a;
char gap_0[3]; /* inserted by compiler: for alignment of b */
int b;
char c;
char gap_1[3]; /* -"-: for alignment of the whole struct in an array */
} x;
Packing, on the other hand prevents compiler ...
C++ lambda with captures as a function pointer
...ector>
#include <functional>
using namespace std;
int ftw(const char *fpath, std::function<int (const char *path)> callback) {
return callback(fpath);
}
int main()
{
vector<string> entries;
std::function<int (const char *fpath)> callback = [&](const char *fpa...
C语言结构体里的成员数组和指针 - c++1y / stl - 清泛IT社区，为创新赋能！
...#include <stdio.h>
struct str{
int len;
char s[0];
};
struct foo {
struct str *a;
};
int main(int argc, char** argv) {
struct foo f={0};
if (f.a->s) {
printf( f.a->s);
&...
Difference between String replace() and replaceAll()
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In java.lang.String, the replace method either takes a pair of char's or a pair of CharSequence's (of which String is a subclass, so it'll happily take a pair of String's). The replace method will replace all occurrences of a char or CharSequence. On the other hand, both String arguments...
Avoid trailing zeroes in printf()
...") the number to a string buffer then manipulate the string to only have N characters past the decimal point.
Assuming your number is in the variable num, the following function will remove all but the first N decimals, then strip off the trailing zeros (and decimal point if they were all zeros).
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Undefined reference to static constexpr char[]
I want to have a static const char array in my class. GCC complained and told me I should use constexpr , although now it's telling me it's an undefined reference. If I make the array a non-member then it compiles. What is going on?
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Java String - See if a string contains only numbers and not letters
...> 2) {
Instead of checking that the string doesn't contain alphabetic characters, check to be sure it contains only numerics.
If you actually want to use the numeric value, use Integer.parseInt() or Double.parseDouble() as others have explained below.
As a side note, it's generally consider...
error C2664: “find_char”: 不能将参数 1 从“const char [14]”转换为“...
error C2664: “find_char”: 不能将参数 1 从“const char [14]”转换为“std::string &出错代码：#include <iostream>#include <string>using std::cout;using std::endl;using std::string; const引用形参举例 非const...出错代码：
#include <iostream>
#include <string>
using...
char类型移动跨平台踩过的坑 - C/C++ - 清泛网 - 专注IT技能提升
char类型移动跨平台踩过的坑CFLAG-fsigned-charchar 跨平台 arm fsigned-charchar强转int时，发现在x86平台下是按照有符号处理的，但是在ARM32下被当成了无符号导致问题，ARM64正常有符号。经调查，在PC上，char类型默认为signed-char,但是在一...