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Display name of the current file in vim?
How do you display the filename of the file you are working on in vim?
9 Answers
9
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How to allocate aligned memory only using the standard library?
...
Original answer
{
void *mem = malloc(1024+16);
void *ptr = ((char *)mem+16) & ~ 0x0F;
memset_16aligned(ptr, 0, 1024);
free(mem);
}
Fixed answer
{
void *mem = malloc(1024+15);
void *ptr = ((uintptr_t)mem+15) & ~ (uintptr_t)0x0...
Git hangs while writing objects
...d in my situation (old school solution none the less but a fresh restart really helped).
– twknab
Mar 23 '17 at 16:59
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Get the name of an object's type
...nstance (2).constructor.name is "Number".
But here are various hacks that all fall down in one way or another:
Here is a hack that will do what you need - be aware that it modifies the Object's prototype, something people frown upon (usually for good reason)
Object.prototype.getName = function() { ...
How to flatten tree via LINQ?
...lt;T>> f
) => e.SelectMany(c => f(c).Flatten(f)).Concat(e);
Call this function like this:
IEnumerable<MyNode> tree = ....
var res = tree.Flatten(node => node.Elements);
If you would prefer flattening in pre-order rather than in post-order, switch around the sides of the Con...
Double decimal formatting in Java
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Optionally u might want to add another separator for digits more than 3 before the comma then use the following NumberFormat formatter = new DecimalFormat("#,000.00"); System.out.println(formatter.format(4.0));
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Pull request vs Merge request
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@stevemao can we access them? Are they really read only as we can resolve conflicts on them?
– Robert Koritnik
Dec 27 '15 at 9:41
12
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What is the most accurate way to retrieve a user's correct IP address in PHP?
.... In a few minutes I will update the code.
– Corey Ballou
Jan 9 '10 at 13:37
35
-1 this is vulne...
Shortcut to create properties in Visual Studio?
I have seen some people creating properties in C# really fast, but how did they do it?
16 Answers
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What would cause an algorithm to have O(log n) complexity?
...er dividing n in half i times we'll have a value that is at most 1. The smallest i for which this is guaranteed is roughly log2 n, so if we have an algorithm that divides by 2 until the number gets sufficiently small, then we can say that it terminates in O(log n) steps.
An important detail is tha...