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Reading settings from app.config or web.config in .NET
... choose the "Add References" option from the Menu.
And from the .NET tab, select System.Configuration. This would include the System.Configuration DLL file into your project.
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MySQL Workbench Dark Theme
...there somewhere else within the Workbench GUI that I need to go to see and select a theme? Besides under "Edit->Preferences-> Fonts & Colors
– edo101
May 7 at 18:54
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What is the shortcut in IntelliJ IDEA to find method / functions?
...> Keyboard > Use all F1, F2, etc. keys as standard function keys
is selected, then the shortcut becomes
CMD + F12
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How to reference a .css file on a razor view?
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How does this allow me to selectively apply a style sheet per view?
– MrBoJangles
Mar 31 '17 at 16:45
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No generic implementation of OrderedDictionary?
...;TKey> Keys {
get {
return _keyedCollection.Select(x => x.Key).ToList();
}
}
public ICollection<TValue> Values {
get {
return _keyedCollection.Select(x => x.Value).ToList();
}
}
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Visual Studio: Is there a way to collapse all items of Solution Explorer?
...stalled, you can right click on the solution in the solution explorer, and select "Collapse All".
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How can I remove the extension of a filename in a shell script?
...also known as separator) for cutting the string into segments and by -f we select which segment we want to have in output
Then the $() command substitution will get the output and return its value
The returned value will be assigned to the variable named name
Note that this gives the portion of th...
Subclipse svn:ignore
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After doing what is mentioned in the solution, select the folder and use the shortcut (Ctrl + Alt + I) to add it to ignore. I don't know why this works and the menu doesn't, it might be a bug.
– Andrei B.
Mar 4 '13 at 10:22
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Android emulator failed to allocate memory 8
... +1 This works to me. Maybe it is because when I specified the ram size I select 1 GB.
– Eng.Fouad
Dec 14 '12 at 4:23
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Add new value to an existing array in JavaScript [duplicate]
...with indexes is not working for me. I am using it inside a map function $('select[id^="filter_"]').map(function () { var name = $(this).prop('name'); filters[name] = $(this).val();
– Happy Coder
Dec 5 '13 at 11:12
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