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Convert integer to string Jinja

... I found the answer. Cast integer to string: myOldIntValue|string Cast string to integer: myOldStrValue|int share | improve this answer ...
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Creating Unicode character from its number

... Just cast your int to a char. You can convert that to a String using Character.toString(): String s = Character.toString((char)c); EDIT: Just remember that the escape sequences in Java source code (the \u bits) are in HEX, so ...
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How to throw std::exceptions with variable messages?

...lt;< foo << 13 << ", bar" << myData); // implicitly cast to std::string throw std::runtime_error(Formatter() << foo << 13 << ", bar" << myData >> Formatter::to_str); // explicitly cast to std::string ...
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Sql Server string to date conversion

... Try this Cast('7/7/2011' as datetime) and Convert(varchar(30),'7/7/2011',102) See CAST and CONVERT (Transact-SQL) for more details. share | ...
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How to get rid of `deprecated conversion from string constant to ‘char*’` warnings in GCC?

...alise strings that will be modified, because they are of type const char*. Casting away the constness to later modify them is undefined behaviour, so you have to copy your const char* strings char by char into dynamically allocated char* strings in order to modify them. Example: #include <iostr...
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Java: Date from unix timestamp

... The cast to (long) is very important: without it the integer overflows. – mneri Jun 11 '14 at 17:18 2 ...
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How to determine if a string is a number with C++?

... You can do it the C++ way with boost::lexical_cast. If you really insist on not using boost you can just examine what it does and do that. It's pretty simple. try { double x = boost::lexical_cast<double>(str); // double could be anything with >> operato...
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C++ templates Turing-complete?

...= config::position }; typedef typename Conditional< static_cast<int>(GetSize<typename config::input>::value) <= static_cast<int>(position), AppendItem<InputBlank, typename config::input>, Identity<typename config::input>&g...
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How do I convert Word files to PDF programmatically? [closed]

...ScreenUpdating = false; foreach (FileInfo wordFile in wordFiles) { // Cast as Object for word Open method Object filename = (Object)wordFile.FullName; // Use the dummy value as a placeholder for optional arguments Document doc = word.Documents.Open(ref filename, ref oMissing, ...
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Test if a property is available on a dynamic variable

... @ministrymason If you mean casting to IDictionary and work with that, that works only on ExpandoObject, it won't work on any other dynamic object. – svick Jul 12 '12 at 16:58 ...