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Counting the number of option tags in a select tag in jQuery
How do I count the number of <option> s in a <select> DOM element using jQuery?
8 Answers
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Remove Select arrow on IE
I have select element, i want to remove the arrow, then i can add other icon..
i can do that for Firefox Safari and Chrome,
but this didn't work on IE9 .
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Selecting data from two different servers in SQL Server
How can I select data in the same query from two different databases that are on two different servers in SQL Server?
15 An...
How to deal with SQL column names that look like SQL keywords?
...ange the name because I didn't make it.
Am I allowed to do something like SELECT from FROM TableName or is there a special syntax to avoid the SQL Server being confused?
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Regex select all text between tags
What is the best way to select all the text between 2 tags - ex: the text between all the 'pre' tags on the page.
17 Answe...
Select data from date range between two dates
...uch more simple (only two cases against four).
Your SQL will look like:
SELECT * FROM Product_sales
WHERE NOT (From_date > @RangeTill OR To_date < @RangeFrom)
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How to round an average to 2 decimal places in PostgreSQL?
... round that takes a precision is only available for numeric.
regress=> SELECT round( float8 '3.1415927', 2 );
ERROR: function round(double precision, integer) does not exist
regress=> \df *round*
List of functions
Schema | Name | Result data type | Argument...
Get/pick an image from Android's built-in Gallery app programmatically
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https://github.com/hanscappelle/SO-2169649
(note that the multiple file selection still needs work)
Single Picture Selection
With support for images from file explorers thanks to user mad.
public class BrowsePictureActivity extends Activity {
// this is the action code we use in our inten...
MySQL Conditional Insert
...
If your DBMS does not impose limitations on which table you select from when you execute an insert, try:
INSERT INTO x_table(instance, user, item)
SELECT 919191, 123, 456
FROM dual
WHERE NOT EXISTS (SELECT * FROM x_table
WHERE user = ...
GROUP BY with MAX(DATE) [duplicate]
... to your group by clause, otherwise you need to rethink your query.
Try:
SELECT t.Train, t.Dest, r.MaxTime
FROM (
SELECT Train, MAX(Time) as MaxTime
FROM TrainTable
GROUP BY Train
) r
INNER JOIN TrainTable t
ON t.Train = r.Train AND t.Time = r.MaxTime
...