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How do I create an array of strings in C?
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If you don't want to change the strings, then you could simply do
const char *a[2];
a[0] = "blah";
a[1] = "hmm";
When you do it like this you will allocate an array of two pointers to const char. These pointers will then be set to the addresses of the static strings "blah" and "hmm".
If you do...
How to convert a char array to a string?
Converting a C++ string to a char array is pretty straightorward using the c_str function of string and then doing strcpy . However, how to do the opposite?
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std::wstring VS std::string
...s between std::string and std::wstring . I know wstring supports wide characters such as Unicode characters. I have got the following questions:
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How to do scanf for single char in C [duplicate]
In C:
I'm trying to get char from the user with scanf and when I run it the program don't wait for the user to type anything...
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Convert a String In C++ To Upper Case
...upper case. The examples I have found from googling only have to deal with chars.
29 Answers
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Why is String.chars() a stream of ints in Java 8?
In Java 8, there is a new method String.chars() which returns a stream of int s ( IntStream ) that represent the character codes. I guess many people would expect a stream of char s here instead. What was the motivation to design the API this way?
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Get an object properties list in Objective-C
...nt; i++) {
objc_property_t property = properties[i];
const char *propName = property_getName(property);
if(propName) {
const char *propType = getPropertyType(property);
NSString *propertyName = [NSString stringWithCString:propName
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How to append a char to a std::string?
...ing fails with the error prog.cpp:5:13: error: invalid conversion from ‘char’ to ‘const char*’
13 Answers
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C语言结构体里的成员数组和指针 - c++1y / stl - 清泛IT社区，为创新赋能！
...#include <stdio.h>
struct str{
int len;
char s[0];
};
struct foo {
struct str *a;
};
int main(int argc, char** argv) {
struct foo f={0};
if (f.a->s) {
printf( f.a->s);
&...
error C2664: “find_char”: 不能将参数 1 从“const char [14]”转换为“...
error C2664: “find_char”: 不能将参数 1 从“const char [14]”转换为“std::string &出错代码：#include <iostream>#include <string>using std::cout;using std::endl;using std::string; const引用形参举例 非const...出错代码：
#include <iostream>
#include <string>
using...