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Change type of varchar field to integer: “cannot be cast automatically to type integer”
...rying ". I'm trying to change it to " Integer " but it gives an error that casting is not possible.
8 Answers
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Flags to enable thorough and verbose g++ warnings
... when you enable a flag that enables multiple warnings, but you want to be selective about it.
– Tamás Szelei
Mar 25 '12 at 22:26
1
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How to get current timestamp in milliseconds since 1970 just the way Java gets
...hrono>
// ...
using namespace std::chrono;
milliseconds ms = duration_cast< milliseconds >(
system_clock::now().time_since_epoch()
);
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improve this answer
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Alternative to itoa() for converting integer to string C++? [duplicate]
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boost::lexical_cast works pretty well.
#include <boost/lexical_cast.hpp>
int main(int argc, char** argv) {
std::string foo = boost::lexical_cast<std::string>(argc);
}
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How to check if a database exists in SQL Server?
...script:
DECLARE @dbname nvarchar(128)
SET @dbname = N'Senna'
IF (EXISTS (SELECT name
FROM master.dbo.sysdatabases
WHERE ('[' + name + ']' = @dbname
OR name = @dbname)))
-- code mine :)
PRINT 'db exists'
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Why does Math.Floor(Double) return a value of type Double?
...ow that the value will actually be within the range of int or long, so you cast it:
double d = 1000.1234d;
int x = (int) Math.Floor(d);
but the onus for that cast is on the developer, not on Math.Floor itself. It would have been unnecessarily restrictive to make it just fail with an exception for...
TypeScript and field initializers
...but doesn't look like it will happen yet.
For comparison, If you use the casting approach, your initialiser object must have ALL the fields for the type you are casting to, plus don't get any class specific functions (or derivations) created by the class itself.
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How do you append an int to a string in C++? [duplicate]
...;
text += oss.str();
Finally, the Boost libraries provide boost::lexical_cast, which wraps around the stringstream conversion with a syntax like the built-in type casts.
#include <boost/lexical_cast.hpp>
text += boost::lexical_cast<std::string>(i);
This also works the other way aro...
Java generics T vs Object
...ct
Foo newFoo = (Foo) my.doSomething(foo);
Two advantages:
no need of casting (the compiler hides this from you)
compile time safety that works. If the Object version is used, you won't be sure that the method always returns Foo. If it returns Bar, you'll have a ClassCastException, at runtime.
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PostgreSQL, checking date relative to “today”
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select * from mytable where mydate > now() - interval '1 year';
If you only care about the date and not the time, substitute current_date for now()
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