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jQuery get selected option value (not the text, but the attribute 'value')

... 04/2020: Corrected old answer Use :selected psuedo selector on the selected options and then use the .val function to get the value of the option. $('select[name=selector] option').filter(':selected').val() Side note: Using filter is better then using :sele...
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Why does AngularJS include an empty option in select?

...efined in the specification at http://docs.angularjs.org/api/ng.directive:select , I still get an empty option as the first child of select element. ...
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jQuery Get Selected Option From Dropdown

Usually I use $("#id").val() to return the value of the selected option, but this time it doesn't work. The selected tag has the id aioConceptName ...
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How to pass parameters on onChange of html select

...avaScript and jQuery. I want to show one combobox-A, which is an HTML <select> with its selected id and contents at the other place on onChange(). ...
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Best way to unselect a in jQuery?

What is the best way, using jQuery, to elegantly unselect the option? 15 Answers 15 ...
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Difference between EXISTS and IN in SQL?

...way to avoid counting: --this statement needs to check the entire table select count(*) from [table] where ... --this statement is true as soon as one match is found exists ( select * from [table] where ... ) This is most useful where you have if conditional statements, as exists can be a lot ...
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How to set selected value on select using selectpicker plugin from bootstrap

I'm using the Bootstrap-Select plugin like this: 18 Answers 18 ...
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Check if option is selected with jQuery, if not select a default

Using jQuery, how do you check if there is an option selected in a select menu, and if not, assign one of the options as selected. ...
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Best way to select random rows PostgreSQL

I want a random selection of rows in PostgreSQL, I tried this: 12 Answers 12 ...
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Can you create nested WITH clauses for Common Table Expressions?

..., the form of the statement you are looking for would be WITH x AS ( SELECT * FROM MyTable ), y AS ( SELECT * FROM x ) SELECT * FROM y share | improve this answer | ...