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Best Practices: working with long, multiline strings in PHP?
...t from the rest of the text and variables also stand out better if you use concatenation rather than inject them inside double quoted string. So I might do something like this with your original example:
$text = 'Hello ' . $vars->name . ','
. "\r\n\r\n"
. 'The second line starts two ...
How to insert newline in string literal?
... = string.Format("first line{0}second line", Environment.NewLine);
String concatenation:
string x = "first line" + Environment.NewLine + "second line";
String interpolation (in C#6 and above):
string x = $"first line{Environment.NewLine}second line";
You could also use \n everywhere, and repl...
How do I pass the value (not the reference) of a JS variable to a function? [duplicate]
....length===0? arguments : arguments.length===0? args :
args.concat(Array.prototype.slice.call(arguments, 0))
);
};
};
}
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Selecting last element in JavaScript array [duplicate]
...
Just use arr.concat().pop()
– 吴毅凡
May 12 at 8:26
...
javascript function leading bang ! syntax
...= 2 statement isn't terminated due to the following parenthesis.
Also in concatenated javascript files you don't have to worry if the preceding code has missing semicolons. So no need for the common ;(function(){})(); to make sure your own won't break.
I know my answer is kind of late but i think...
Merging dictionaries in C#
...K,V> src in
(new List<IDictionary<K,V>> { me }).Concat(others)) {
// ^-- echk. Not quite there type-system.
foreach (KeyValuePair<K,V> p in src) {
newMap[p.Key] = p.Value;
}
}
return newMap;
}
}...
Is It Possible to Sandbox JavaScript Running In the Browser?
...; // object: object q=1 w=2
}
}).eval({
code : "[1, 2, 3].concat(input)",
input : [4, 5, 6],
callback: function(arr) {
console.log("array: ", arr); // array: [1, 2, 3, 4, 5, 6]
}
}).eval({
code : "function x(z){this.y=z;};new x(input)",
...
How do I group Windows Form radio buttons?
...Many(ctrl => GetAll(ctrl, type))
.Concat(controls)
.Where(c => c.GetType() == type);
}
}
}
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impr...
Get name of property as a string
... var expression = GetMemberInfo(property);
string path = string.Concat(expression.Member.DeclaringType.FullName,
".", expression.Member.Name);
// Do ExposeProperty work here...
}
}
public class Program
{
public static void Main()
{
RemoteMgr.Expose...
Why is the shovel operator (
...erators) which is an assignment. On the other hand << is an alias of concat() which alters the receiver in-place.
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