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Is there a way to get the source code from an APK file?
...e that you want to decode.
Now rename the extension of this .apk file to .zip (e.g. rename from filename.apk to filename.zip) and save it. Now you can access the classes.dex files, etc. At this stage you are able to see drawables but not xml and java files, so continue.
Step 2:
Now extract this ...
Python element-wise tuple operations like sum
...
tuple([item1 + item2 for item1, item2 in zip(a, b)]) would be the equivalent as a list comprehension.
– Adam Parkin
Feb 13 '12 at 21:20
13
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How to get certain commit from GitHub project
... to the right side of the commit name/message, and finally on the Download ZIP button that comes when you click Clone or Download button.
I hope it helps you guys.
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将 App Inventor 2 项目连接到外部传感器 · App Inventor 2 中文网
...路 在线 客服 扫码添加客服咨询 我要 分享 扫码分享到朋友圈 顶部 var qrcode = new QRCode("qrcode", { text: window.location.href + "?f=share", //...
App Inventor 2 中文网原创内容 · App Inventor 2 中文网
...器、USB
【连接调试】Ai2 Starter模拟器下载及安装
【代码调试】App Inventor 2 代码调试方式：App调试、问题排查
【项目合并】AI2项目合并工具
【存储】Android存储系统基础知识：内部存储，外部存储，App特定目录ASD 及 getASD代...
图表组件 · App Inventor 2 中文网
...用程序的设计视图中设置 图表数据 属性，或使用设置代码块。如果关联的 二维图表数据 发生变化，趋势线将自动更新。
趋势线有四种模型：线性、二次、对数和指数。根据您使用的模型，趋势线组件的某些属性将提供相关值...
更改MFC对话框默认的窗口类名 - C/C++ - 清泛网 - 专注C/C++及内核技术
...），如果存在，我们就不再创建程序的新进程，而仅仅是激活它。FindWindow函数的声明为：
HWND FindWindow(
LPCTSTR lpClassName,
LPCTSTR lpWindowName
);
我们可以通过窗口类名（lpClassName）查找，也可以通过窗口标题文本（lpWind...
Which mime type should I use for mp3
...riation of a mime type for a specific file. I was trying to upload mp3 and zip files with open source php class, that what I have found:
Firefox (mp3): audio/mpeg
Firefox (zip): application/zip
Chrome (mp3): audio/mp3
Chrome (zip): application/octet-stream
Opera (mp3): audio/mp3
Opera (zip):...
Pandas: create two new columns in a dataframe with values calculated from a pre-existing column
...
I'd just use zip:
In [1]: from pandas import *
In [2]: def calculate(x):
...: return x*2, x*3
...:
In [3]: df = DataFrame({'a': [1,2,3], 'b': [2,3,4]})
In [4]: df
Out[4]:
a b
0 1 2
1 2 3
2 3 4
In [5]: df["A1"], ...
Convert a list to a dictionary in Python
...
b = dict(zip(a[::2], a[1::2]))
If a is large, you will probably want to do something like the following, which doesn't make any temporary lists like the above.
from itertools import izip
i = iter(a)
b = dict(izip(i, i))
In Python...