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Open soft keyboard programmatically
I have an activity with no child widgets for it and the corresponding xml file is,
23 Answers
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How to get last N records with activerecord?
...e-wise - at least not up to Rails 3.1. SomeModel.last(5) will execute the select statement without a limit, returning all records of SomeModel to Ruby as an array, after which Ruby will pick out the last (5) elements. Efficiency-wise, currently, you want to use limit - particularly if you have pote...
jQuery: Select data attributes that aren't empty?
I'm trying to select all elements that have a data-go-to attribute that is not empty.
11 Answers
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MySQL root access from all hosts
...to comment out the line in your my.cnf file:
#bind-address = 127.0.0.1
and restart mysql
service mysql restart
By default it binds only to localhost, but if you comment the line it binds to all interfaces it finds. Commenting out the line is equivalent to bind-address=*.
To check where mysql...
How do I check if an index exists on a table field in MySQL?
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Try:
SELECT * FROM information_schema.statistics
WHERE table_schema = [DATABASE NAME]
AND table_name = [TABLE NAME] AND column_name = [COLUMN NAME]
It will tell you if there is an index of any kind on a certain column wi...
fs: how do I locate a parent folder?
... answered Aug 16 '11 at 18:22
Andrew HareAndrew Hare
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Android Studio with Google Play Services
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Go to File -> Project Structure
Select 'Project Settings'
Select 'Dependencies' Tab
Click '+' and select '1.Library Dependencies'
Search for : com.google.android.gms:play-services
Select the latest version and click 'OK'
Voila! No need to fight with Grad...
How to delete or add column in SQLITE?
... as long as you do a create new table first instead of a create from select, it will have all those things.
– John Lord
Jul 3 '19 at 15:28
1
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Create a completed Task
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Just checked the latest VS 14 CTP and created a 4.5.3 project, Task.CompletedTask is still internal.
– Peter Ritchie
Oct 14 '14 at 16:54
1...
Mysql error 1452 - Cannot add or update a child row: a foreign key constraint fails
... have to get rid of those first.
Here's a query that can find those IDs:
SELECT DISTINCT sourcecode_id FROM
sourcecodes_tags tags LEFT JOIN sourcecodes sc ON tags.sourcecode_id=sc.id
WHERE sc.id IS NULL;
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