大约有 43,000 项符合查询结果（耗时：0.0486秒） [XML]
Is there an XSLT name-of element?
...
This will give you the current element name (tag name)
<xsl:value-of select ="name(.)"/>
OP-Edit: This will also do the trick:
<xsl:value-of select ="local-name()"/>
share
|
impro...
Can I have multiple Xcode versions installed?
... explicitly specify it at install time. Also, you will generally want to unselect all features besides the xcode core tools, because the others don't let you change the install directory.
– Paul Du Bois
Jul 3 '11 at 3:30
...
Access-control-allow-origin with multiple domains
...r paths = new List<string>(AppSettings.whiteListDomainCors.Split(new char[] { ',' }));
foreach (var value in paths)
{
current.Add(value);
}
}
}
I found this guide online and it worked like a charm :
http://jnye.co/Posts/2032/dynamic-cors-origins-from-...
byte + byte = int… why?
...ly thing that happened is an addition of 2 ints.
– RichardTheKiwi
Apr 3 '11 at 23:22
2
...
Python argparse ignore unrecognised arguments
...r "recognized" arguments instead.
parser = argparse.ArgumentParser(prefix_chars='+')
parser.add_argument('+cd')
The same command will produce
Namespace(_unrecognized_args=['--foo', 'BAR', 'a', 'b'], cd='e')
Put that in your pipe and smoke it =)
nJoy!
...
Select a Dictionary with LINQ
I have used the "select" keyword and extension method to return an IEnumerable<T> with LINQ, but I have a need to return a generic Dictionary<T1, T2> and can't figure it out. The example I learned this from used something in a form similar to the following:
...
Split column at delimiter in data frame [duplicate]
...OO=c('a|b','b|c','x|y'))
foo <- data.frame(do.call('rbind', strsplit(as.character(df$FOO),'|',fixed=TRUE)))
Or, if you want to replace the columns in the existing data.frame:
within(df, FOO<-data.frame(do.call('rbind', strsplit(as.character(FOO), '|', fixed=TRUE))))
Which produces:
ID ...
Select all 'tr' except the first one
How can I select all tr elements except the first tr in a table with CSS?
10 Answers
...
Maximum Year in Expiry Date of Credit Card
...orget that in most browsers you can still key in the number and it'll auto select.
– Kevin Wiskia
Mar 22 '11 at 19:44
1
...
How to include “zero” / “0” results in COUNT aggregate?
...n outer join for this (and you need to use person as the "driving" table)
SELECT person.person_id, COUNT(appointment.person_id) AS "number_of_appointments"
FROM person
LEFT JOIN appointment ON person.person_id = appointment.person_id
GROUP BY person.person_id;
The reason why this is working, i...