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How to convert a Bitmap to Drawable in android?
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That's deprecated now. Use the BitmapDrawable(Resources, Bitmap) constructor now.
– schlingel
Jan 16 '13 at 11:55
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How to empty a list in C#?
...ds 5 equal answers?):
list.Add(5);
// list contains at least one element now
list = new List<int>();
// list in "list" is empty now
Keep in mind that all other references to the old list have not been cleared (depending on the situation, this might be what you want). Also, in terms of perf...
best way to get the key of a key/value javascript object
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You can now use spread operator for this purpose, it looks better: const [firstKey, ...rest] = Object.keys(obj);
– Nerlin
Dec 13 '17 at 21:08
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How do I read configuration settings from Symfony2 config.yml?
...gmail.com
You should find the call you are making within your controller now works.
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PHP Sort Array By SubArray Value
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Now also as closure:-- usort($array, function($a,$b){ return $b["optionNumber"] - $a["optionNumber"]; });
– Joeri
Dec 3 '14 at 20:34
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Android - Handle “Enter” in an EditText
...mpossible" and so on, usually without code. Often his answers are outdated now, so I try not to follow his recommendations.
– CoolMind
Feb 4 '19 at 10:22
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bash/fish command to print absolute path to a file
...will still give you a valid path given some relative path. If you want to know about file existence use another tool like e.g. test.
– Benjamin Bannier
Feb 27 '13 at 17:47
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How to make rounded percentages add up to 100%
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@VarunVohra sorry i didn't notice this until now, yes it looks like your algorithm is the same :) not sure why my post is the accepted answer, the obfuscated code was just for the lolz...
– yonilevy
Mar 31 '14 at 10:40
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Upload files with HTTPWebrequest (multipart/form-data)
... url));
string boundary = "---------------------------" + DateTime.Now.Ticks.ToString("x");
byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" + boundary + "\r\n");
HttpWebRequest wr = (HttpWebRequest)WebRequest.Create(url);
wr.ContentType = "multipa...
Can two applications listen to the same port?
... requests coming from a certain IP and the other to another remote IP?
I know I can have one application that starts off two threads (or forks) to have similar behavior, but can two applications that have nothing in common do the same?
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