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How to trim a string to N chars in Javascript?

... And if you want ellipses for strings exceeding the max length (probably more helpful for longer max): var string = "this is a string"; var length = 20; var trimmedString = string.length > length ? string.substring(0, leng...
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How do I specify “close existing connections” in sql script

I'm doing active development on my schema in SQL Server 2008 and frequently want to rerun my drop/create database script. When I run ...
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Replacing instances of a character in a string

... Strings in python are immutable, so you cannot treat them as a list and assign to indices. Use .replace() instead: line = line.replace(';', ':') If you need to replace only certain semicolons, you'll need to be more specific. You could use slicing to isolate the section of the string to r...
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Scala type programming resources

... time. I will try to draw parallels between programming at the value-level and programming at the type-level. Paradigms There are two main paradigms in type-level programming: "object-oriented" and "functional". Most examples linked to from here follow the object-oriented paradigm. A good, fairly...
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How do I toggle an element's class in pure JavaScript?

... 2014 answer: classList.toggle() is the standard and supported by most browsers. Older browsers can use use classlist.js for classList.toggle(): var menu = document.querySelector('.menu') // Using a class instead, see note below. menu.classList.toggle('hidden-phon...
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How do I format a date in Jinja2?

... There are two ways to do it. The direct approach would be to simply call (and print) the strftime() method in your template, for example {{ car.date_of_manufacture.strftime('%Y-%m-%d') }} Another, sightly better approach would be to define your own filter, e.g.: from flask import Flask import b...
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Is it possible to make a div 50px less than 100% in CSS3? [duplicate]

...rrently supported in the 3 main browsers: Firefox, Google Chrome (WebKit), and IE9: http://caniuse.com/calc MDN: https://developer.mozilla.org/en/CSS/-moz-calc share | improve this answer ...
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One-liner to check whether an iterator yields at least one element?

...s at first success easily: run any((x > 100 for x in xrange(10000000))) and then run any((x > 10000000 for x in xrange(100000000))) -- the second should take much longer. – chbrown Apr 18 '12 at 19:53 ...
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Removing numbers from string [closed]

...t()]) >>> result 'abcd' This makes use of a list comprehension, and what is happening here is similar to this structure: no_digits = [] # Iterate through the string, adding non-numbers to the no_digits list for i in s: if not i.isdigit(): no_digits.append(i) # Now join all e...
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Auto column width in EPPlus

... return null if there's no data in the worksheet. – Landeeyo Jan 23 '15 at 10:22 @Landeeyo Thanks it helps for me. It ...