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converting drawable resource image into bitmap
...
409
You probably mean Notification.Builder.setLargeIcon(Bitmap), right? :)
Bitmap largeIcon = Bitm...
How can I get a resource content from a static context?
... setText on widgets, so how can I do that without an activity object to call getResources() on?
14 Answers
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再说WCF Data Contract KnownTypeAttribute - 更多技术 - 清泛网移动版 - 专注C/C++及内核技术
...aredTypes>
<add type="WcfServiceDemo.Address, MyAssembly, Version=2.0.0.0, Culture=neutral,PublicKeyToken=null, processorArchitecture=MSIL">
<knownType type="MyCompany.Library.Circle, MyAssembly, Version=2.0.0.0, Culture=neutral, PublicKeyToken=null, processorArchitecture=MSIL"/>
...
Bash script to calculate time elapsed
...
10 Answers
10
Active
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Maven Snapshot Repository vs Release Repository
... development. A Snapshot artifact has both a version number such as “1.3.0” or “1.3” and a timestamp. For example, a snapshot artifact for commons-lang 1.3.0 might have the name commons-lang-1.3.0-20090314.182342-1.jar.
Taken from refcard
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Use of class definitions inside a method in Java
...
This is called a local class.
2 is the easy one: yes, a class file will be generated.
1 and 3 are kind of the same question. You would use a local class where you never need to instantiate one or know about implementation details a...
How do I convert an integer to binary in JavaScript?
...
function dec2bin(dec){
return (dec >>> 0).toString(2);
}
dec2bin(1); // 1
dec2bin(-1); // 11111111111111111111111111111111
dec2bin(256); // 100000000
dec2bin(-256); // 11111111111111111111111100000000
You can use Number.toString(2) function, but it has ...
Suppress properties with null value on ASP.NET Web API
...ueHandling = NullValueHandling.Ignore
}
};
config.Formatters.RemoveAt(0);
config.Formatters.Insert(0, jsonformatter);
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How do I get the name of captured groups in a C# Regex?
...oupName in regex.GetGroupNames())
{
Console.WriteLine(
"Group: {0}, Value: {1}",
groupName,
groups[groupName].Value);
}
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How do I convert a string to a double in Python?
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>>> x = "2342.34"
>>> float(x)
2342.3400000000001
There you go. Use float (which behaves like and has the same precision as a C,C++, or Java double).
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