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Refactoring in Vim
...Ag, :Ggrep
Refactoring that has more to do with regular replacements I usually use :grep on my project tree and then record a macro to do the refactor - :g and :s are no brainers. Usually it'll let me quickly modify a large number of files with very little effort. Honestly, I use this method more t...
How to trim leading and trailing white spaces of a string?
... Denys SéguretDenys Séguret
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2
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Format / Suppress Scientific Notation from Python Pandas Aggregation Results
...float_format', lambda x: '%.3f' % x)
In [28]: Series(np.random.randn(3))*1000000000
Out[28]:
0 -757322420.605
1 -1436160588.997
2 -1235116117.064
dtype: float64
I'm not sure if that's the preferred way to do this, but it works.
Converting numbers to strings purely for aesthetic purposes ...
Maven check for updated dependencies in repository
...lable:
[INFO] org.apache.maven:maven-artifact ........................ 2.0 -> 2.0.9
[INFO] org.apache.maven:maven-plugin-api ...................... 2.0 -> 2.0.9
[INFO] org.apache.maven:maven-project ....................... 2.0.2 -> 2.0.9
[INFO] org.codehaus.plexus:plexus-utils ........
PHP cURL HTTP CODE return 0
I dont understand when I echo $httpCode I always get 0, I was expecting 404 when I change $html_brand into a broken url. Is there anything that I miss or do not know of? Thanks.
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Generate random int value from 3 to 6
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10 Answers
10
Active
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What is “point free” style (in Functional Programming)?
...you specify the arguments explicitly):
sum (x:xs) = x + (sum xs)
sum [] = 0
Point-free (sum doesn't have any explicit arguments - it's just a fold with + starting with 0):
sum = foldr (+) 0
Or even simpler: Instead of g(x) = f(x), you could just write g = f.
So yes: It's closely related to c...
Android RelativeLayout programmatically Set “centerInParent”
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401
Completely untested, but this should work:
View positiveButton = findViewById(R.id.positiveBut...
Play sound on button click android
...ick? I just created a button with id button1 , but whatever code I write, all is wrong.
11 Answers
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Iterating over a numpy array
...>>> for (x,y), value in numpy.ndenumerate(a):
... print x,y
...
0 0
0 1
1 0
1 1
2 0
2 1
Regarding the performance. It is a bit slower than a list comprehension.
X = np.zeros((100, 100, 100))
%timeit list([((i,j,k), X[i,j,k]) for i in range(X.shape[0]) for j in range(X.shape[1]) for k...