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Find the day of a week
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df = data.frame(date=c("2012-02-01", "2012-02-01", "2012-02-02"))
df$day <- weekdays(as.Date(df$date))
df
## date day
## 1 2012-02-01 Wednesday
## 2 2012-02-01 Wednesday
## 3 2012-02-02 Thursday
Edit: Just to show another way...
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Does ruby have real multithreading?
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612
Updated with Jörg's Sept 2011 comment
You seem to be confusing two very different things here...
How do I get the fragment identifier (value after hash #) from a URL?
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No need for jQuery
var type = window.location.hash.substr(1);
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Get query string parameters url values with jQuery / Javascript (querystring)
...n use this new API to get values from the location!
// Assuming "?post=1234&action=edit"
var urlParams = new URLSearchParams(window.location.search);
console.log(urlParams.has('post')); // true
console.log(urlParams.get('action')); // "edit"
console.log(urlParams.getAll('action')); // ["ed...
Why are elementwise additions much faster in separate loops than in a combined loop?
Suppose a1 , b1 , c1 , and d1 point to heap memory and my numerical code has the following core loop.
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Check if a string contains an element from a list (of strings)
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how to get the last character of a string?
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Best way to simulate “group by” from bash?
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Removing duplicate objects with Underscore for Javascript
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