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What can be the reasons of connection refused errors?
... its backlog of pending connections is full.
A firewall between the client and server is blocking access (also check local firewalls).
After checking for firewalls and that the port is open, use telnet to connect to the ip/port to test connectivity. This removes any potential issues from your appl...
A Windows equivalent of the Unix tail command [closed]
I'm looking for the equivalent of the Unix 'tail' command that will allow me to watch the output of a log file while it is being written to.
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Wait for a process to finish
... solution for MacOS that does not use polling.
– Alexander Mills
Feb 28 '18 at 16:58
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Intersection and union of ArrayLists in Java
...tal = (ArrayList<String>) intersection(list2, list1) --->cannot cast java.util.arraylist to java.util.arraylist<string>
– user3402040
Feb 11 '16 at 9:34
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What is the syntax for an inner join in LINQ to SQL?
... value of the enum. If I'm right, (ContactStatus)c.StatusID is really just casting an integer to an enum.
– Joel Mueller
Jul 14 '10 at 22:13
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How to check if IEnumerable is null or empty?
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Count() only iterates the enumeration if it can't be cast to an ICollection. In other words, when you call this method, if there's already a Count property on the object, it will just return that and the performance should be identical. Check out the implementation here: refere...
How to change the background color of the options menu?
...arent="Theme.AppCompat.Light.DarkActionBar">
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<item name="android:itemBackground">@color/overflow_background</item>
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</style>
Tested from API 4.2 to 5.0.
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How to stop/terminate a python script from running?
I wrote a program in IDLE to tokenize text files and it starts to tokeniza 349 text files! How can I stop it? How can I stop a running Python program?
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Insert a row to pandas dataframe
... as both objects are of the same type. Maybe the issue is that you need to cast your second vector to a dataframe? Using the df that you defined the following works for me:
df2 = pd.DataFrame([[2,3,4]], columns=['A','B','C'])
pd.concat([df2, df])
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How to create a button programmatically?
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As of Swift 1.2 downcasts can no longer be done with "as", they must be “forced failable” with "as!".
– TenaciousJay
May 1 '15 at 16:38
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