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Nodejs - Redirect url
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@Magic Not true. Try Location: / and it would redirect you to the root folder.
– user3459110
Oct 24 '14 at 5:35
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How to use continue in jQuery each() loop?
In my application i am using AJAX call. I want to use break and continue in this jQuery loop.
4 Answers
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Remove a folder from git tracking
...oint of view (i.e. they are in past history, but not in the latest commit, and people pulling from this repo will get the files removed from their trees), but stay on your working directory because you've used --cached.
shar...
is_file or file_exists in PHP
...rk to work, you should add clearstatcache(); since the results for is_file and file_exists are cached throughout the script. Anyways file_exists() is a bit slower, but shouldn't make any difference unless you perform around 100K file checks. php.net/manual/en/function.clearstatcache.php
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in_array multiple values
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Intersect the targets with the haystack and make sure the intersection is precisely equal to the targets:
$haystack = array(...);
$target = array('foo', 'bar');
if(count(array_intersect($haystack, $target)) == count($target)){
// all of $target is in $haysta...
How to make a new line or tab in XML (eclipse/android)?
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Add \t for tab and \n for new line.
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Including a .js file within a .js file [duplicate]
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I basically do like this, create new element and attach that to <head>
var x = document.createElement('script');
x.src = 'http://example.com/test.js';
document.getElementsByTagName("head")[0].appendChild(x);
You may also use onload event to each script you atta...
json.net has key method?
If my response has key "error" I need to process error and show warning box.
3 Answers
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How can I discover the “path” of an embedded resource?
...tility
{
/// <summary>
/// Takes the full name of a resource and loads it in to a stream.
/// </summary>
/// <param name="resourceName">Assuming an embedded resource is a file
/// called info.png and is located in a folder called Resources, it
/// will be co...
Python xml ElementTree from a string source?
... The problem is that ElementTree.fromstring generates an element, and not an ElementTree! Anyone knows how to work around this?
– Samuel Lampa
Nov 16 '12 at 17:13
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