大约有 48,000 项符合查询结果(耗时:0.0545秒) [XML]

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Using group by on multiple columns

..., to do with who is attending what subject at a university: Table: Subject_Selection +---------+----------+----------+ | Subject | Semester | Attendee | +---------+----------+----------+ | ITB001 | 1 | John | | ITB001 | 1 | Bob | | ITB001 | 1 | Mickey | | ITB001 ...
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Return rows in random order [duplicate]

... SELECT * FROM table ORDER BY NEWID() share | improve this answer | follow | ...
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Detect if value is number in MySQL

... This should work in most cases. SELECT * FROM myTable WHERE concat('',col1 * 1) = col1 It doesn't work for non-standard numbers like 1e4 1.2e5 123. (trailing decimal) share ...
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MySQL get row position in ORDER BY

... Use this: SELECT x.id, x.position, x.name FROM (SELECT t.id, t.name, @rownum := @rownum + 1 AS position FROM TABLE t JOIN (SELECT @rownum := 0) r ORDER BY t.name)...
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SELECT INTO using Oracle

I'm trying to do a SELECT INTO using Oracle. My query is: 3 Answers 3 ...
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How do I add options to a DropDownList using jQuery?

...lugins, var myOptions = { val1 : 'text1', val2 : 'text2' }; var mySelect = $('#mySelect'); $.each(myOptions, function(val, text) { mySelect.append( $('<option></option>').val(val).html(text) ); }); If you had lots of options, or this code needed to be run very ...
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How do I query if a database schema exists

... Are you looking for sys.schemas? IF NOT EXISTS (SELECT * FROM sys.schemas WHERE name = 'jim') BEGIN EXEC('CREATE SCHEMA jim') END Note that the CREATE SCHEMA must be run in its own batch (per the answer below) ...
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Insert Data Into Temp Table with Query

... SELECT * INTO #Temp FROM (SELECT Received, Total, Answer, (CASE WHEN application LIKE '%STUFF%' THEN 'MORESTUFF' END) AS application FROM FirstTable WHERE Recieved = 1 AND applicati...
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SQL: How to properly check if a record exists

... It's better to use either of the following: -- Method 1. SELECT 1 FROM table_name WHERE unique_key = value; -- Method 2. SELECT COUNT(1) FROM table_name WHERE unique_key = value; The first alternative should give you no result or one result, the second count should be zero or on...
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Finding duplicate values in a SQL table

... SELECT name, email, COUNT(*) FROM users GROUP BY name, email HAVING COUNT(*) > 1 Simply group on both of the columns. Note: the older ANSI standard is to have all non-aggregated columns in the GROUP BY ...