大约有 43,000 项符合查询结果(耗时:0.0319秒) [XML]
SQLite with encryption/password protection
...ing str)
{
byte[] bytes = new byte[str.Length * sizeof(char)];
bytes = System.Text.Encoding.Default.GetBytes(str);
return bytes;
}
}
}
Optionally, you can remove conn.SetPassword(passwordBytes);, and replace it with conn.ChangePassword("passw...
SELECT * FROM X WHERE id IN (…) with Dapper ORM
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Dapper supports this directly. For example...
string sql = "SELECT * FROM SomeTable WHERE id IN @ids"
var results = conn.Query(sql, new { ids = new[] { 1, 2, 3, 4, 5 }});
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imp...
std::string to float or double
...e temp = winOpacity.toDouble();
Extra note:
If the input data is a const char*, QByteArray::toDouble will be faster.
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What is the maximum length of a valid email address?
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An email address must not exceed 254 characters.
This was accepted by the IETF following submitted erratum. A full diagnosis of any given address is available online. The original version of RFC 3696 described 320 as the maximum length, but John Klensin subsequ...
How can I find the last element in a List?
...ndLast(_ => true);, but I find just the underscore (or any other single character identifier) can be a bit confusing at times.
– Bob
Jan 29 '13 at 5:56
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Get list of all tables in Oracle?
...
SELECT owner, table_name
FROM dba_tables
This is assuming that you have access to the DBA_TABLES data dictionary view. If you do not have those privileges but need them, you can request that the DBA explicitly grants you...
List all sequences in a Postgres db 8.1 with SQL
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The following query gives names of all sequences.
SELECT c.relname FROM pg_class c WHERE c.relkind = 'S';
Typically a sequence is named as ${table}_id_seq. Simple regex pattern matching will give you the table name.
To get last value of a sequence use the following query:...
Java: Clear the console
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System.out.println(new String(new char[50]).replace("\0", "\r\n")); will do the job faster and better.
– Aaron Esau
Dec 30 '17 at 0:28
1
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PostgreSQL DISTINCT ON with different ORDER BY
...llowing approaches:
The general solution that should work in most DBMSs:
SELECT t1.* FROM purchases t1
JOIN (
SELECT address_id, max(purchased_at) max_purchased_at
FROM purchases
WHERE product_id = 1
GROUP BY address_id
) t2
ON t1.address_id = t2.address_id AND t1.purchased_at = t2...
How do I do top 1 in Oracle?
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If you want just a first selected row, you can:
select fname from MyTbl where rownum = 1
You can also use analytic functions to order and take the top x:
select max(fname) over (rank() order by some_factor) from MyTbl
...
