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JQuery Event for user pressing enter in a textbox?
...e for some keys, better to use e.which, this will guarantee that you will handle same button on every browser
– Oleg Shakhov
Feb 1 at 15:09
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How do I provide custom cast support for my class?
...ypes? For example, if I have my own implementation of managing a byte[] , and I want to let people cast my class to a byte[] , which will just return the private member, how would I do this?
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How to make a div with no content have a width?
...eight because it doesn't force a height. Say your font-size is set to 16px and your padding is 15px. Your div will retain the same height before and after text is added to the div (assuming it's all on one line)
– eroedig
Jul 16 '15 at 18:56
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How to check 'undefined' value in jQuery
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JQuery library was developed specifically to simplify and to unify certain JavaScript functionality.
However if you need to check a variable against undefined value, there is no need to invent any special method, since JavaScript has a typeof operator, which is simple, fast and...
Call a function after previous function is complete
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Specify an anonymous callback, and make function1 accept it:
$('a.button').click(function(){
if (condition == 'true'){
function1(someVariable, function() {
function2(someOtherVariable);
});
}
else {
doThis(som...
Check if a variable is of function type
...swered Sep 9 '11 at 2:24
Alex GrandeAlex Grande
6,85311 gold badge2323 silver badges2727 bronze badges
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Working with Enums in android
I am almost done with a calculation activity I am working with in android for my app. I try to create a Gender Enum, but for some reason getting Syntax error, insert "EnumBody" to complete EnumDeclaration.
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Making a Sass mixin with optional arguments
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A DRY'r Way of Doing It
And, generally, a neat trick to remove the quotes.
@mixin box-shadow($top, $left, $blur, $color, $inset:"") {
-webkit-box-shadow: $top $left $blur $color #{$inset};
-moz-box-shadow: $top $left $blur $color #{$inset};
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How to select rows with no matching entry in another table?
I'm doing some maintenance work on a database application and I've discovered that, joy of joys, even though values from one table are being used in the style of foreign keys, there's no foreign key constraints on the tables.
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Check if instance is of a type
... A small note: use "is" if you don't want to use the result of the cast and use "as" if you do.
– Aviram Fireberger
Nov 10 '15 at 14:55
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