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Failed to import new Gradle project: failed to find Build Tools revision *.0.0
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This is the most straightforward answer as of now. Thanks!
– Steven Carlton
Nov 15 '16 at 22:22
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Can I get “&&” or “-and” to work in PowerShell?
...:
build
if ($?) {
run_tests
}
2019/11/27: The &&operator is now available for PowerShell 7 Preview 5+:
PS > echo "Hello!" && echo "World!"
Hello!
World!
share
|
improve ...
How to “log in” to a website using Python's Requests module?
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I know you've found another solution, but for those like me who find this question, looking for the same thing, it can be achieved with requests as follows:
Firstly, as Marcus did, check the source of the login form to get thre...
Recommended way of making React component/div draggable
...nd could probably even wrap it in a nice closure interface, but I want to know if there's a way that meshes with React better.
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Why did Rails4 drop support for “assets” group in the Gemfile
...ion) like coffee-rails if you are using coffee templates
and the fact that now assets are not precompiled on demand in production anymore.
(not precompiled on demand in production) Means that if you have that gems in production environment in 3.2.x and forget to precompile, Rails will do exactly wha...
What's the fastest way to loop through an array in JavaScript?
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The blog post this answer is based on is now almost 4 years old, and a lot has changed in js engines in that time, see my answer below for an updated comparison.
– jondavidjohn
Aug 31 '11 at 3:01
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data.frame rows to a list
...mp;
}
res.attr("names") = x.attr("row.names");
return res;
}
Now caompare with purrr:
benchmark(
purrr = by_row(x, function(v) list(v)[[1L]], .collate = "list")$.out,
rcpp = df2list(x)
)
Results:
Benchmark summary:
Time units : milliseconds
expr n.eval min lw.qu median m...
Difference between SurfaceView and View?
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FYI...A SurfaceView can now be transparent: stackoverflow.com/questions/5391089/…
– Steve
Apr 17 '12 at 20:15
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How to find the kth largest element in an unsorted array of length n in O(n)?
...∑i=floor(n/2) to n T(i)
<= cn + 2 (1/n) ∑i=floor(n/2) to n ai
and now somehow we have to get the horrendous sum on the right of the plus sign to absorb the cn on the left. If we just bound it as 2(1/n) ∑i=n/2 to n an, we get roughly 2(1/n)(n/2)an = an. But this is too big - there's no r...
Scale image to fit a bounding box
...n it's container, and CSS can't do this.
The reason is that CSS does not know what the page looks like. It sets rules beforehand, but only after that it is that the elements get rendered and you know exactly what sizes and ratios you're dealing with. The only way to detect that is with JavaScript.
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