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select and update database record with a single queryset
How do I run an update and select statements on the same queryset rather than having to do two queries:
- one to select the object
- and one to update the object
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Adding a library/JAR to an Eclipse Android project
...w application project.
When you are creating the library project, you can select any application name, package, and set other fields as needed, as shown in figure 1.
Next, set the project's properties to indicate that it is a library project:
In the Package Explorer, right-click the library proje...
SQL Server: Filter output of sp_who2
... SPID_1 INT,
REQUESTID INT
)
INSERT INTO @Table EXEC sp_who2
SELECT *
FROM @Table
WHERE ....
And filter on what you require.
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C/C++ with GCC: Statically add resource files to executable/library
...t uniform, then char is probably the most convenient: take its address and cast the pointer to the proper type as you traverse the data.
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jQuery set radio button
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Your selector looks for the descendant of a input:radio[name=cols] element that has the id of newcol (well the value of that variable).
Try this instead (since you're selecting by ID anyway):
$('#' + newcol).prop('checked',true)...
Selecting the first “n” items with jQuery
With Jquery, I need to select just the first "n" items from the page, for example the first 20 links instead of selecting all of them with the usual
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SQL Server: What is the difference between CROSS JOIN and FULL OUTER JOIN?
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select COUNT_BIG(*) FROM Traffic t CROSS JOIN Recipient r and SELECT COUNT_BIG(*) FROM Traffic t FULL JOIN Recipient r ON (1=1) they are the same.
– urlreader
Sep 20 '13 at 21:02
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How to select bottom most rows?
I can do SELECT TOP (200) ... but why not BOTTOM (200)?
14 Answers
14
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Get day of week in SQL Server 2005/2008
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Use DATENAME or DATEPART:
SELECT DATENAME(dw,GETDATE()) -- Friday
SELECT DATEPART(dw,GETDATE()) -- 6
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LINQ - Left Join, Group By, and Count
...into j1
from j2 in j1.DefaultIfEmpty()
group j2 by p.ParentId into grouped
select new { ParentId = grouped.Key, Count = grouped.Count(t=>t.ChildId != null) }
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