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LINQ - Full Outer Join
I have a list of people's ID and their first name, and a list of people's ID and their surname. Some people don't have a first name and some don't have a surname; I'd like to do a full outer join on the two lists.
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Process escape sequences in a string in Python
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hands down, the best solution! btw, by docs it should be "string_escape" (with underscore) but for some reason accepts anything in the pattern 'string escape', 'string@escape" and whatnot... basically 'string\W+escape'
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Get Slightly Lighter and Darker Color from UIColor
...the brightness property itself. All in all:
@implementation UIColor (LightAndDark)
- (UIColor *)lighterColor
{
CGFloat h, s, b, a;
if ([self getHue:&h saturation:&s brightness:&b alpha:&a])
return [UIColor colorWithHue:h
saturation:s
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How to find serial number of Android device?
I need to use a unique ID for an Android app and I thought the serial number for the device would be a good candidate. How do I retrieve the serial number of an Android device in my app ?
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How does Facebook disable the browser's integrated Developer Tools?
... the recent scams, the developer tools is exploited by people to post spam and even used to "hack" accounts. Facebook has blocked the developer tools, and I can't even use the console.
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Converting a Java collection into a Scala collection
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JavaConversions (robinst's answer) and JavaConverters (Ben James's answer) have been deprecated with Scala 2.10.
Instead of JavaConversions use:
import scala.collection.convert.wrapAll._
as suggested by aleksandr_hramcov.
Instead of JavaConverters use:
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How to install GCC piece by piece with GMP, MPFR, MPC, ELF, without shared libraries?
...s of dependencies, not using a package manager (like yum, rpm, apt, dpkg), and not using shared libraries?
6 Answers
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Is main() really start of a C++ program?
The section $3.6.1/1 from the C++ Standard reads,
11 Answers
11
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'printf' vs. 'cout' in C++
What is the difference between printf() and cout in C++?
16 Answers
16
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How to enumerate a range of numbers starting at 1
...o do in Python 2.6 or newer:
enumerate(range(2000, 2005), 1)
Python 2.5 and older do not support the start parameter so instead you could create two range objects and zip them:
r = xrange(2000, 2005)
r2 = xrange(1, len(r) + 1)
h = zip(r2, r)
print h
Result:
[(1, 2000), (2, 2001), (3, 2002), ...