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How to check if my string is equal to null?
...mpty, false otherwise
return myString.isEmpty() // Returns `true` if this char sequence is empty (contains no characters), false otherwise
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How to use `string.startsWith()` method ignoring the case?
... really will do a toUpperCase in a 1mb String just to compare 4-10 inicial characters?
– Dyorgio
Apr 7 '16 at 16:52
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The simplest way to comma-delimit a list?
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The StringJoiner class.
Example:
// Util method for strings and other char sequences
List<String> strs = Arrays.asList("1", "2", "3");
String listStr1 = String.join(",", strs);
// For any type using streams and collectors
List<Object> objs = Arrays.asList(1, 2, 3);
String listStr2 ...
Regex, every non-alphanumeric character except white space or colon
... - matches all the letters
^ - negates them all - so you get - non numeric chars, non spaces and non colons
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Why should I use a pointer rather than the object itself?
...m (especially when using IDEs or text editors that show the signature of a selected functions). Also, const&.
– JAB
Mar 3 '14 at 16:04
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How do I remove all specific characters at the end of a string in PHP?
How do I remove the last character only if it's a period?
9 Answers
9
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Numeric for loop in Django templates
... center creates a string of n spaces that are then looped over. Each space char is then ignored, but the current value in range can be found from forloop.counter (or forloop.counter0). See docs.djangoproject.com/en/dev/ref/templates/builtins/#center
– isedwards
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In Java, what is the best way to determine the size of an object?
... primitives but then you don't really need a program to tell you how big a char is.
– Brel
Sep 16 '11 at 12:39
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How to create a directory using Ansible
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this uses the old syntax with = chars, would be great to update it with the : syntax with each atribute on a new line
– ympostor
Jun 8 '17 at 7:52
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Extract month and year from a zoo::yearmon object
...an extract the date parts as required:
> format(date1, "%b") ## Month, char, abbreviated
[1] "Mar"
> format(date1, "%Y") ## Year with century
[1] "2012"
> format(date1, "%m") ## numeric month
[1] "03"
These are returned as characters. Where appropriate, wrap in as.numeric() if you want t...