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Access to the path is denied
...e me too! In my case I should add that I am annoyed that an HttpPostedFileBase object's SaveAs method required a name in addition to the path, considering the name is another property on the object. Of course I guess you could give it a different name this way.
– Ralph
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How do I force a DIV block to extend to the bottom of a page even if it has no content?
...ere's not enough content to fill the available vertical browser viewport:
Demo at (drag the frame handle to see effect) : http://jsfiddle.net/NN7ky
(upside: clean, simple. downside: requires flexbox - http://caniuse.com/flexbox)
HTML:
<body>
<div class=div1>
div1<br>
...
Is it good style to explicitly return in Ruby?
..., another programmer (perhaps not that familiar with how Ruby does returns based on last line of code executed) comes along and wants to put in some print statements for logging, and the function becomes this...
def plus_one_to_y(x)
@y = x + 1
puts "In plus_one_to_y"
end
Now the function ...
Lambda function in list comprehensions
...(map(lambda x: x*x, range(10))) will give you [0, 1, 4, 9, 16, 25, 36, 49, 64, 81]
– rrlamichhane
Jun 12 at 22:58
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Printf width specifier to maintain precision of floating-point value
...ces for an exact representation of the value if an exact representation in base 2 exists and otherwise is sufficiently large to distinguish values of type double.
I'd have to add that this is only available since C99.
shar...
Can't pickle when using multiprocessing Pool.map()
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Can you please update this answer based on pathos.pp because pathos.multiprocessing doesn't exist anymore?
– Saheel Godhane
Apr 23 '15 at 20:06
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Why does SIGPIPE exist?
...HELPING ICE
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Most efficient way to create a zero filled JavaScript array?
...rays - with 1M elements - you can perform test HERE
Conclusions
solution based on new Array(n)+for (N) is fastest solution for small arrays and big arrays (except Chrome but still very fast there) and it is recommended as fast cross-browser solution
solution based on new Float32Array(n) (I) return...
Expand a random range from 1–5 to 1–7
...will run in a constant amount of time, since 1/7 is an infinite decimal in base 5. One simple solution would be to use rejection sampling, e.g.:
int i;
do
{
i = 5 * (rand5() - 1) + rand5(); // i is now uniformly random between 1 and 25
} while(i > 21);
// i is now uniformly random between 1...
Custom attributes in styles.xml
... for help, clarification, or responding to other answers.Making statements based on opinion; back them up with references or personal experience.To learn more, see our tips on writing great answers.
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