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How to generate a random string of a fixed length in Go?
...te, n)
for i := range b {
b[i] = letterBytes[rand.Int63() % int64(len(letterBytes))]
}
return string(b)
}
This works and is significantly faster, the disadvantage is that the probability of all the letters will not be exactly the same (assuming rand.Int63() produces all 63-bit ...
Unmangling the result of std::type_info::name
...
}
#endif
Usage:
#include <iostream>
#include "type.hpp"
struct Base { virtual ~Base() {} };
struct Derived : public Base { };
int main() {
Base* ptr_base = new Derived(); // Please use smart pointers in YOUR code!
std::cout << "Type of ptr_base: " << type(ptr_base...
Can CSS detect the number of children an element has?
... misleading. Note that, in CSS3, styles cannot be applied to a parent node based on the number of children it has. However, styles can be applied to the children nodes based on the number of siblings they have.
Original answer:
Incredibly, this is now possible purely in CSS3.
/* one item */
li:...
What does string::npos mean in this code?
...can not be negative... real meaning is max_index, 18446744073709551615 for 64 bit size_t
– NoSenseEtAl
Sep 4 '14 at 12:33
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What are the dangers when creating a thread with a stack size of 50x the default?
...date 1), using an i7 4700 MQ, under .NET 4.5.1
I tested both with x86 and x64 and the results are identical.
Edit: I increased the stack size of all threads 201 MB, the sample size to 50 million and decreased iterations to 5.
The results are the same as above:
Stack-allocated array time: 00:00...
Deep Learning(深度学习)学习笔记整理系列之(二) - 大数据 & AI - 清泛...
...往往由一些基本结构组成。比如下图:一个图可以通过用64种正交的edges(可以理解成正交的基本结构)来线性表示。比如样例的x可以用1-64个edges中的三个按照0.8,0.3,0.5的权重调和而成。而其他基本edge没有贡献,因此均为0 。
...
Deep Learning(深度学习)学习笔记整理系列之(二) - 大数据 & AI - 清泛...
...往往由一些基本结构组成。比如下图:一个图可以通过用64种正交的edges(可以理解成正交的基本结构)来线性表示。比如样例的x可以用1-64个edges中的三个按照0.8,0.3,0.5的权重调和而成。而其他基本edge没有贡献,因此均为0 。
...
Deep Learning(深度学习)学习笔记整理系列之(二) - 大数据 & AI - 清泛...
...往往由一些基本结构组成。比如下图:一个图可以通过用64种正交的edges(可以理解成正交的基本结构)来线性表示。比如样例的x可以用1-64个edges中的三个按照0.8,0.3,0.5的权重调和而成。而其他基本edge没有贡献,因此均为0 。
...
Deep Learning(深度学习)学习笔记整理系列之(二) - 大数据 & AI - 清泛...
...往往由一些基本结构组成。比如下图:一个图可以通过用64种正交的edges(可以理解成正交的基本结构)来线性表示。比如样例的x可以用1-64个edges中的三个按照0.8,0.3,0.5的权重调和而成。而其他基本edge没有贡献,因此均为0 。
...
Deep Learning(深度学习)学习笔记整理系列之(二) - 大数据 & AI - 清泛...
...往往由一些基本结构组成。比如下图:一个图可以通过用64种正交的edges(可以理解成正交的基本结构)来线性表示。比如样例的x可以用1-64个edges中的三个按照0.8,0.3,0.5的权重调和而成。而其他基本edge没有贡献,因此均为0 。
...