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Why can't variable names start with numbers?
...names are "numbers+alpha that don't parse to a valid numeric designation", and that's just silly.
– eaolson
Oct 11 '09 at 3:56
4
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Make a div fill up the remaining width
...(see note 1).
The great advantage is that now you can specify a max-width and a min-width to your left & right elements. Which is fantastic for fluid layouts.. hence responsive layout :-)
note 1: versus Leigh's answer where you need to add the margin-left & margin-right properties to the "...
RESTful on Play! framework
... render(user);
}
As you can see I only removed the getUserJSON method and renamed the getUser method. For different content types to work you now have to create several templates. One for each desired content type. For example:
user.xml:
<users>
<user>
<name>${user.nam...
Build Android Studio app via command line
I want to build an Android Studio app (the Gradle build system), but I want to do this via the command line.
12 Answers
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Permutations in JavaScript?
...s into an array prior to do any permutation, so you simply remove the join and split operation
var permArr = [],
usedChars = [];
function permute(input) {
var i, ch;
for (i = 0; i < input.length; i++) {
ch = input.splice(i, 1)[0];
usedChars.push(ch);
if (input.leng...
Creating JS object with Object.create(null)?
...= Object.prototype while Object.create(null) doesn't inherit from anything and thus has no properties at all.
In other words: A javascript object inherits from Object by default, unless you explicitly create it with null as its prototype, like: Object.create(null).
{} would instead be equivalent t...
Update one MySQL table with values from another
...ue = original.value)
SET tobeupdated.id = original.id
That should do it, and really its doing exactly what yours is. However, I prefer 'JOIN' syntax for joins rather than multiple 'WHERE' conditions, I think its easier to read
As for running slow, how large are the tables? You should have indexes...
How to set a value of a variable inside a template code?
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It seems you cannot declare a container (I've tried list and tuple) in a with clause
– Vladislav Ivanishin
Mar 18 '15 at 1:58
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How to resolve “must be an instance of string, string given” prior to PHP 7?
...Prior to PHP 7 type hinting can only be used to force the types of objects and arrays. Scalar types are not type-hintable. In this case an object of the class string is expected, but you're giving it a (scalar) string. The error message may be funny, but it's not supposed to work to begin with. Give...
Using CSS in Laravel views?
I've just began learning Laravel, and can do the basics of a controller and routing.
18 Answers
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