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How to find indices of all occurrences of one string in another in JavaScript?
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new RegExp(searchStr) would be the way, and yes, in the general case you would have to escape special characters. It's not really worth doing unless you need that level of generality.
– Tim Down
Aug 4 '10 at 23:43
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How to redirect to previous page in Ruby On Rails?
I have a page that lists all of the projects that has sortable headers and pagination.
7 Answers
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HTTP header line break style
...ch line break style is preferable for use in HTTP headers: \r\n or \n , and why?
3 Answers
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How do I create a right click context menu in Java Swing?
...g a right-click context menu by instantiating a new JMenu on right click and setting its location to that of the mouse's position... Is there a better way?
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Numeric for loop in Django templates
... a simple technique that works nicely for small cases with no special tags and no additional context. Sometimes this comes in handy
{% for i in '0123456789'|make_list %}
{{ forloop.counter }}
{% endfor %}
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“elseif” syntax in JavaScript
... people ask questions like this.. I think it shows a fundamental misunderstanding. With if and else there really is no need of elseif.
– mpen
Oct 23 '10 at 21:12
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How to check what version of jQuery is loaded?
...'t know how to check it. If they have it loaded how do I check the version and the prefix such as:
11 Answers
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Does Firefox support position: relative on table elements?
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Easy and most proper way would be to wrap the contents of the cell in a div and add position:relative to that div.
example:
<td>
<div style="position:relative">
This will be positioned normally
<div ...
GitHub: make fork an “own project”
...t it seems the original author hasn't got the time to review these changes and include them. In fact, it is even possible that the features I need and implemented are not in the vision of the original author and we simply aim at different goals. I don't know as I never got responses from him.
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Cast List to List
...use now there are two separate lists. This is safe, but you need to understand that changes made to one list won't be seen in the other list. (Modifications to the objects that the lists refer to will be seen, of course.)
sh...